Home
Class 12
PHYSICS
A beam of 13.0 eV electrons is used to b...

A beam of `13.0 eV` electrons is used to bombard gaseous hydrogen. The series obtained in emission spectra is // are

A

Lyman series

B

Balmer series

C

Brackett series

D

All of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the emission series obtained when a beam of 13.0 eV electrons bombards gaseous hydrogen, we will follow these steps: ### Step 1: Understand the Energy Levels of Hydrogen The energy levels of the hydrogen atom can be described by the formula: \[ E_n = -\frac{13.6 \text{ eV}}{n^2} \] where \( n \) is the principal quantum number (n = 1, 2, 3, ...). ### Step 2: Calculate the Energy of the First Few Levels - For \( n = 1 \): \[ E_1 = -\frac{13.6 \text{ eV}}{1^2} = -13.6 \text{ eV} \] - For \( n = 2 \): \[ E_2 = -\frac{13.6 \text{ eV}}{2^2} = -3.4 \text{ eV} \] - For \( n = 3 \): \[ E_3 = -\frac{13.6 \text{ eV}}{3^2} \approx -1.51 \text{ eV} \] - For \( n = 4 \): \[ E_4 = -\frac{13.6 \text{ eV}}{4^2} = -0.85 \text{ eV} \] - For \( n = 5 \): \[ E_5 = -\frac{13.6 \text{ eV}}{5^2} \approx -0.544 \text{ eV} \] ### Step 3: Determine the Maximum Excitation Level The energy provided to the electrons is 13.0 eV. To find out how far the electrons can be excited, we need to calculate the energy difference between the ground state and the excited state: \[ \text{Energy provided} = 13.0 \text{ eV} - (-13.6 \text{ eV}) = 13.0 + 13.6 = 26.6 \text{ eV} \] This means the electrons can be excited to a level where the total energy is less than or equal to 0 eV. ### Step 4: Find the Maximum n Value We need to find the maximum \( n \) such that: \[ E_n \geq -13.0 \text{ eV} \] From the energy level formula: \[ -\frac{13.6}{n^2} \geq -13.0 \] This simplifies to: \[ \frac{13.6}{n^2} \leq 13.0 \implies n^2 \geq \frac{13.6}{13.0} \approx 1.046 \] Thus, \( n \) can be 1 or higher. ### Step 5: Identify Possible Emission Series The electrons can de-excite from the maximum level they reach. The maximum level can be calculated as follows: - If the electrons reach \( n = 4 \) (as determined from energy levels), they can de-excite to: - \( n = 3 \) (Paschen series) - \( n = 2 \) (Balmer series) - \( n = 1 \) (Lyman series) ### Conclusion The possible emission series are: - Lyman series (from \( n=2 \) to \( n=1 \)) - Balmer series (from \( n=3 \) to \( n=2 \)) - Paschen series (from \( n=4 \) to \( n=3 \)) ### Final Answer The series obtained in the emission spectra are the **Lyman series, Balmer series, and Paschen series**. ---

To solve the problem of determining the emission series obtained when a beam of 13.0 eV electrons bombards gaseous hydrogen, we will follow these steps: ### Step 1: Understand the Energy Levels of Hydrogen The energy levels of the hydrogen atom can be described by the formula: \[ E_n = -\frac{13.6 \text{ eV}}{n^2} \] where \( n \) is the principal quantum number (n = 1, 2, 3, ...). ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Multiple Correct|13 Videos
  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Linked Comprehension|62 Videos
  • ATOMIC PHYSICS

    CENGAGE PHYSICS ENGLISH|Exercise Subject|17 Videos
  • ALTERNATING CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|10 Videos
  • CAPACITOR AND CAPACITANCE

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

Similar Questions

Explore conceptually related problems

A 12.5eV electron beam is used to bombard gaseous hydrogen at room temperature. What serious of wavelength will be emitted?

A 12.9 eV beam of electrons is used to bombard gaseous hydrogen atom at room temperature. Up to which energy level the hydrogen atoms would be excited? Calculate the wavelength of the first member of Paschen series and first member of Balmer series.

Knowledge Check

  • Assertion: Hydrogen atom consists of anly one electron but its emission spectrum has may lines. Reason: Only Lyman series is found in the absorption spectrum of hydrogen atom whereas in the emission spectrum, all the series are found.

    A
    if both assertion and reason are true and reason is the correct explanation of assertion.
    B
    if both assertion and reason are true but reason is not the correct explanation of assertion.
    C
    if assertion is true but reason is false.
    D
    if both assertion and reason are false.
  • Similar Questions

    Explore conceptually related problems

    A 12.5 eV electron beam is used to bombard gaseous hydrogen at room temperature. Upto which energy. Level the hydrogen atoms would be excited ? Calculate the wavelengths of the first memeber of Lyman and first member of Balmer series.

    Electrons having kinetic energy 30 eV are made to collide with atomic hydrogen gas (in ground state) and 42.5% of electron energy is used to excite the hydrogen wavelength in emission spectra are

    A 12.5 eV electron beam is used to excite a gaseous hydrogen atom at room temperature. Determine the wavelengths and the corresponding series of the lines emitted.

    The electron in hydrogen atom in a sample is in n^(th) excited state, then the number of differrent spectrum lines obtained in its emission spectrum will be

    The ionization energy of the electron in the lowest orbit of hydrogen atom is 13.6 eV. The energies required in eV to remove an electron from three lowest energy orbits of hydrogen atom respectively are

    In photons of energy 12.75 eV are passing through hydrogen gas in ground state then no. of lines in emission spectrum will be

    which of the following series belong to the visible region of emission spectra?