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The pressure P, Volume V and temperature...

The pressure P, Volume V and temperature T of a gas in the jar A and the other gas in the jar B at pressure `2P`, volume `V//4` and temperature `2 T`, then the ratio of the number of molecules in the jar A and B will be

A

`1:1`

B

`1:2`

C

`2:1`

D

`4:1`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of the number of molecules in jar A and jar B, we can use the ideal gas equation, which is given by: \[ PV = nRT \] where: - \( P \) = pressure - \( V \) = volume - \( n \) = number of moles of the gas - \( R \) = universal gas constant - \( T \) = temperature ### Step 1: Write the Ideal Gas Equation for Jar A For jar A, we have: - Pressure = \( P \) - Volume = \( V \) - Temperature = \( T \) Using the ideal gas equation: \[ PV = n_A RT \] where \( n_A \) is the number of moles in jar A. ### Step 2: Write the Ideal Gas Equation for Jar B For jar B, we have: - Pressure = \( 2P \) - Volume = \( \frac{V}{4} \) - Temperature = \( 2T \) Using the ideal gas equation: \[ (2P) \left(\frac{V}{4}\right) = n_B R(2T) \] where \( n_B \) is the number of moles in jar B. ### Step 3: Simplify the Equation for Jar B Simplifying the equation for jar B: \[ \frac{2PV}{4} = n_B (2RT) \] This simplifies to: \[ \frac{PV}{2} = n_B (2RT) \] ### Step 4: Rearranging the Equation for Jar B Now, we can rearrange this to find \( n_B \): \[ n_B = \frac{PV}{4RT} \] ### Step 5: Set Up the Ratio of Number of Moles Now we have two equations: 1. For jar A: \[ n_A = \frac{PV}{RT} \] 2. For jar B: \[ n_B = \frac{PV}{4RT} \] ### Step 6: Calculate the Ratio of Number of Moles Now, we can find the ratio of the number of moles \( n_A \) and \( n_B \): \[ \frac{n_A}{n_B} = \frac{\frac{PV}{RT}}{\frac{PV}{4RT}} \] ### Step 7: Simplifying the Ratio This simplifies to: \[ \frac{n_A}{n_B} = \frac{PV}{RT} \cdot \frac{4RT}{PV} = 4 \] ### Conclusion Thus, the ratio of the number of molecules in jar A to jar B is: \[ \frac{n_A}{n_B} = 4:1 \] ### Final Answer The ratio of the number of molecules in jar A and jar B is \( 4:1 \). ---
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Knowledge Check

  • If P,V, and T represent pressure, volume and temperature of the gas, the correct representation of Boyle's law is

    A
    `V prop (1)/(T)` (P constant)
    B
    ` V prop (1)/(P)` (T constant)
    C
    PV = RT
    D
    PV = nRT
  • The volume of vessel A is twice the volume of another vessel B and both of them are filled with the same gas. If the gas in A is at twice the temperature and twice the pressure in comparison to the gas in B, what is the ratio of number of gas molecule in A and B ?

    A
    `1/2`
    B
    `2/1`
    C
    `3/2`
    D
    `2/3`
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