Home
Class 12
CHEMISTRY
The vapour pressure of pure benzene at 5...

The vapour pressure of pure benzene at `50^(@)` is `268 mm` of `Hg`. How many moles of non-volatile solute per mole of benzene are required to prepare a solution of benzene having a vapour pressure of `16.0 mm` of `Hg` at `50^(@)C`?

Text Solution

AI Generated Solution

To solve the problem, we need to determine how many moles of a non-volatile solute are required to lower the vapor pressure of benzene to 16.0 mm Hg from its pure vapor pressure of 268 mm Hg. ### Step-by-Step Solution: 1. **Identify Given Values**: - Vapor pressure of pure benzene, \( P^0_B = 268 \, \text{mm Hg} \) - Vapor pressure of the solution, \( P_s = 16.0 \, \text{mm Hg} \) ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|40 Videos

  • SOLUTIONS

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Linked Comprehension)|58 Videos

  • SOLID STATE

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.2 (Objective)|9 Videos

  • SURFACE CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|2 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of pure benzene C_(6)H_(6) at 50^(@)C is 268 "torr" . How many moles of non-volatile solute per mole of benzene is required to prepare a solution of benzene having a vapour pressure of 167 "torr" at 50^(@)C ?

The vapour pressure of pure benzene, C_(6)H_(6) at 50^(@)C is 268 Torr. How many moles of non-volatile solute per mol of benzene is required to prepare a solution of benzene is required to prepare a solution of benzenen having a vapour pressure of 167 Torr at 50^(@)C ?

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

The vapour pressure of pure benzene at 25^(@)C is 639.7 mm Hg and vapour pressure of a solution of solute in benzene at the same temperature is 631.9 mm Hg. Calculate the molality of the solution.

The vapour pressure of pure benzene at a certain temperature is 640 mm of Hg . A non-volatile non-electrolyte solid weighing 2.175 g added 39.0 g of benzene. The vapour pressure of the solution is 600 mm of Hg . What is the molecular weight of solid substance?

The vapour pressure of C Cl_4 at 25^@C is 143 mm Hg. If 0.5 gm of a non-volatile solute (mol.weight=65) is dissolved in 100g C Cl_4 , the vapour pressure of the solution will be

The vapour pressure of a pure liquid at 25^(@)C is 100 mm Hg. Calculate the relative lowering of vapour pressure if the mole fraction of solvent in solution is 0.8.

At 293 K, vapour pressure of pure benzene is 75mm of Hg and that of pure toluene is 22 mm of Hg. The vapour pressure of the solution which contains 20 mol% benzene and 80 mol % toluene is

The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is:

Vapour pressure of benzene at 30^(@)C is 121.8 mm. When 15 g of a non-volatile solute is dissolved in 250 g of benzene its vapour pressure decreased to 120.2 mm. The molecular weight of the solute is (mol. Weight of solvent = 78)

Home
Profile