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0.90 gm of an organic compound C(4)H(10)...

`0.90 gm` of an organic compound `C_(4)H_(10)O_(2) (A)` when treated with sodium gives `224 ml` of hydrogen at `NTP`. Compound (A) can be separated into fraction (B) and
(C ), by crystallisation of which the fraction (B) is resolved into isomers (D) and (E ). Write down the structural formula of (A) to (E ) with proper reasoning.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the information given and derive the structural formulas for the compounds A to E. ### Step 1: Determine the Molar Mass of Compound A The molecular formula of compound A is \(C_4H_{10}O_2\). - Calculate the molar mass: \[ \text{Molar mass} = (4 \times 12) + (10 \times 1) + (2 \times 16) = 48 + 10 + 32 = 90 \, \text{g/mol} ...
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