Home
Class 11
CHEMISTRY
Predict the number of stereoisomers in C...

Predict the number of stereoisomers in `CH_(2)OH.(CHOH)_(4).CHO`.

A

16

B

8

C

4

D

2

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of stereoisomers in the compound \( CH_2OH.(CHOH)_4.CHO \), we will follow these steps: ### Step 1: Understand the Structure The compound can be broken down as follows: - It has a terminal \( CH_2OH \) group. - It has four \( CHOH \) groups in the middle. - It ends with a terminal \( CHO \) group. ### Step 2: Draw the Structure The structure can be visualized as: ``` CHO | CH | CH | CH | CH2OH ``` This shows the arrangement of the carbon atoms and their respective functional groups. ### Step 3: Identify Asymmetrical Carbon Atoms An asymmetrical (or chiral) carbon atom is one that has four different groups attached to it. We will analyze each carbon atom in the structure: 1. The terminal \( CH_2OH \) does not contribute as it has two hydrogen atoms. 2. The first \( CH \) connected to \( CHO \) has different groups (CHO, CH2OH, OH, and H) → asymmetrical. 3. The second \( CH \) also has different groups (OH, CH, CH2OH, and H) → asymmetrical. 4. The third \( CH \) has different groups (OH, CH, CH2OH, and H) → asymmetrical. 5. The last \( CH \) connected to \( CH2OH \) does not contribute as it has two hydrogen atoms. Thus, we find that there are **four asymmetrical carbon atoms** in total. ### Step 4: Apply the Stereoisomer Formula The formula for calculating the number of stereoisomers is: \[ \text{Number of stereoisomers} = 2^n \] where \( n \) is the number of asymmetrical carbon atoms. ### Step 5: Calculate the Number of Stereoisomers Since we have identified \( n = 4 \): \[ \text{Number of stereoisomers} = 2^4 = 16 \] ### Conclusion The total number of stereoisomers for the compound \( CH_2OH.(CHOH)_4.CHO \) is **16**. ---

To determine the number of stereoisomers in the compound \( CH_2OH.(CHOH)_4.CHO \), we will follow these steps: ### Step 1: Understand the Structure The compound can be broken down as follows: - It has a terminal \( CH_2OH \) group. - It has four \( CHOH \) groups in the middle. - It ends with a terminal \( CHO \) group. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ISOMERISM

    CENGAGE CHEMISTRY ENGLISH|Exercise Assertion-Reasoning Type (Exercise)|5 Videos
  • ISOMERISM

    CENGAGE CHEMISTRY ENGLISH|Exercise Fill in the blanks (Exercise)|3 Videos
  • ISOMERISM

    CENGAGE CHEMISTRY ENGLISH|Exercise Single correct answer type|13 Videos
  • IONIC EQUILIBRIUM

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Subjective|28 Videos
  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY ENGLISH|Exercise Chemical Equilibrium|73 Videos

Similar Questions

Explore conceptually related problems

Predict the number of stereoisomers for 2,5 heptadiene.

The number of stereoisomers of compound CH_(3)-CH=CH-CH(Br)CH_(3) is :

Knowledge Check

  • Total number of stereoisomers of the compound CH_(3)-CH=CH- underset(OH) underset(|)(CH)-CH=CH-CH_(3) is :

    A
    2
    B
    3
    C
    4
    D
    8
  • Number of stereoisomers of the given compound CH_(3)-CH=CH- overset(OH) overset(|)(CH)-CH_(3) is :

    A
    2
    B
    4
    C
    3
    D
    6
  • Similar Questions

    Explore conceptually related problems

    The number of optical isomers of CH_3CH (OH)CH(OH)CHO is :-

    Write the IUPAC names of CH_(2)OH.CH_(2)CHO

    Write the IUPAC names of CH_(2)OH.CH_(2)CHO

    Write the IUPAC names of CH_(2)OH.CH_(2)CHO

    The name of the compound CH_(3)-CH_(2)-CHO is

    When the following aldohexose exists in its D-configuration, the total number of stereoisomers in its pyranose form is. OHC-CH_(2)-underset(OH)underset("| ")"CH"-underset(OH)underset("| ")"CH"-underset(OH)underset("| ")"CH"-CH_(2)-OH