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Which of the following compounds will no...

Which of the following compounds will not show geometrical isomerism?

A

`3`- Phenyl-`2` propenoic acid

B

`2` Butene

C

`3`- Methyl-`2` butenoic acid

D

`3`- Methyl-2 pentenoic acid.

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The correct Answer is:
To determine which compound will not show geometrical isomerism, we need to analyze the conditions required for geometrical isomerism to occur. Geometrical isomerism typically occurs in compounds with a carbon-carbon double bond (C=C) where each carbon atom in the double bond is attached to two different groups. ### Step-by-Step Solution: 1. **Understand the Conditions for Geometrical Isomerism:** - For a compound to exhibit geometrical isomerism, each carbon in the double bond must be bonded to two different groups. - If either carbon in the double bond has two identical groups, the compound cannot show geometrical isomerism. 2. **Analyze Each Compound:** - **Option 1: 3-Phenyl-2-propanoic acid** - Structure: COOH-CH=CH-Ph (phenyl group) - Around the double bond, we have: - Carbon 1: COOH and H (different groups) - Carbon 2: H and Ph (different groups) - Conclusion: This compound can show geometrical isomerism. - **Option 2: 2-Butene (CH3-CH=CH-CH3)** - Structure: CH3-CH=CH-CH3 - Around the double bond, we have: - Carbon 1: CH3 and H (different groups) - Carbon 2: CH3 and H (different groups) - Conclusion: This compound can show geometrical isomerism. - **Option 3: 3-Methyl-2-butanoic acid** - Structure: CH3-CH=CH-COOH - Around the double bond, we have: - Carbon 1: H and COOH (different groups) - Carbon 2: CH3 and CH3 (same groups) - Conclusion: Since one carbon has two identical groups (CH3), this compound cannot show geometrical isomerism. - **Option 4: 3-Methyl-2-pentanoic acid** - Structure: CH3-CH=CH-COOH - Around the double bond, we have: - Carbon 1: H and COOH (different groups) - Carbon 2: CH3 and CH2CH3 (different groups) - Conclusion: This compound can show geometrical isomerism. 3. **Final Conclusion:** - The compound that will not show geometrical isomerism is **Option 3: 3-Methyl-2-butanoic acid**.

To determine which compound will not show geometrical isomerism, we need to analyze the conditions required for geometrical isomerism to occur. Geometrical isomerism typically occurs in compounds with a carbon-carbon double bond (C=C) where each carbon atom in the double bond is attached to two different groups. ### Step-by-Step Solution: 1. **Understand the Conditions for Geometrical Isomerism:** - For a compound to exhibit geometrical isomerism, each carbon in the double bond must be bonded to two different groups. - If either carbon in the double bond has two identical groups, the compound cannot show geometrical isomerism. ...
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CENGAGE CHEMISTRY ENGLISH-ISOMERISM-Single correct answer type (Exercise)
  1. Predict the number of stereoisomers for 2,5 heptadiene.

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  2. Symbol D stands for:

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  3. Which of the following compounds will not show geometrical isomerism?

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  4. The enolic form of acetone contains:

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  5. Arrange the following in the increasing order of expected enol content...

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  6. The decreasing order of reactivity of the following alkenes is: i. 2...

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  7. Which of the following is the least stable form of cyclohexane?

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  8. The minimum number of carbon atoms an alkane should contain in order t...

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  9. A compound whose molecule is superimposabel on its mirror image despit...

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  10. The IUPAC name of the compound with formula C(n)H(2n+2), having the lo...

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  11. A racemic mixtrue is optically inactive due to :

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  12. The pair of structures given below represents:

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  13. The degree of unsaturation or index of hydrogen deficiency in the foll...

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  14. The degree of unsaturation in i. C(3)H(3)Cl(3), ii. C(3)H(4)O, iii. ...

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  15. Which of the following alkenes is most stable?

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  16. Which of the following will have zero dipole moment?

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  17. The number of conformations exhibited by ethane is

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  18. Which of the following is not an isomer of butanal?

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  19. The least energetic conformation of cyclohexane is:

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  20. How many chiral carbons are present in glucose molecule CHO(CHOH)(4)CH...

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