Which of the following have `sp^(3)` d hyberidisation of the central atom ? .

Options

A. `XeF_(4)`
B. `XeO_(2)F_(2)`
C. `CIO_(3)^(Θ)`
D. `BrF_(3)`

Explanation

To determine which of the given compounds have `sp^3d` hybridization of the central atom, we need to calculate the steric number for each compound. The steric number is calculated as the sum of the number of bond pairs and lone pairs around the central atom.

### Step-by-Step Solution:

1. **Understanding `sp^3d` Hybridization**:
- `sp^3d` hybridization involves the mixing of one s orbital, three p orbitals, and one d orbital, resulting in a total of five hybrid orbitals.
- The steric number for `sp^3d` hybridization is 5.

2. **Calculating Steric Number**:
- The steric number (SN) is calculated using the formula:
\[ \text{Steric Number} = \text{Number of Bond Pairs} + \text{Number of Lone Pairs} \]

3. **Analyzing Each Compound**:
- **Compound 1: XeF4**
- Xe has 8 valence electrons. It forms 4 bonds with F (1 electron each).
- Remaining electrons: \(8 - 4 = 4\) (which form 2 lone pairs).
- Steric number: \(4 \text{ (bond pairs)} + 2 \text{ (lone pairs)} = 6\).
- **Conclusion**: Not `sp^3d`.

- **Compound 2: XeCO2F2**
- Xe forms 2 bonds with O and 2 bonds with F.
- Total bonds: 4, leaving 1 lone pair (since Xe has 8 valence electrons).
- Steric number: \(4 \text{ (bond pairs)} + 1 \text{ (lone pair)} = 5\).
- **Conclusion**: This compound has `sp^3d` hybridization.

- **Compound 3: ClO3-**
- Cl has 7 valence electrons and forms 3 bonds with O.
- Remaining electrons: \(7 - 3 = 4\) (which form 1 lone pair).
- Steric number: \(3 \text{ (bond pairs)} + 1 \text{ (lone pair)} = 4\).
- **Conclusion**: Not `sp^3d`.

- **Compound 4: BrF3**
- Br has 7 valence electrons and forms 3 bonds with F.
- Remaining electrons: \(7 - 3 = 4\) (which form 2 lone pairs).
- Steric number: \(3 \text{ (bond pairs)} + 2 \text{ (lone pairs)} = 5\).
- **Conclusion**: This compound has `sp^3d` hybridization.

4. **Final Answer**:
- The compounds that have `sp^3d` hybridization of the central atom are **XeCO2F2** and **BrF3**.