Which among the following is (are) having two lone pair of electrons on central atom ? .

Options

A. `CO_(2)`
B. `CIF_(3)`
C. `SO_(3)^(2-)`
D. `XeF_(4)`

Explanation

To determine which of the given molecules have two lone pairs of electrons on the central atom, we will follow a systematic approach by calculating the total number of valence electrons, determining the number of bond pairs and lone pairs for each molecule.

### Step-by-Step Solution:

1. **Identify the Molecules**: Let's analyze the given molecules one by one. For this example, we will consider the following molecules:
- A) C2
- B) ClF3
- C) SO3^2- (sulfite ion)
- D) XeF4

2. **Calculate Valence Electrons**:
- **For C2**:
- Carbon (C) has 4 valence electrons.
- Total for C2 = 2 * 4 = 8 valence electrons.
- **For ClF3**:
- Chlorine (Cl) has 7 valence electrons, and each Fluorine (F) has 7 valence electrons.
- Total for ClF3 = 7 + 3 * 7 = 28 valence electrons.
- **For SO3^2-**:
- Sulfur (S) has 6 valence electrons, and each Oxygen (O) has 6 valence electrons.
- With 2 extra electrons due to the -2 charge, total = 6 + 3 * 6 + 2 = 26 valence electrons.
- **For XeF4**:
- Xenon (Xe) has 8 valence electrons, and each Fluorine (F) has 7 valence electrons.
- Total for XeF4 = 8 + 4 * 7 = 36 valence electrons.

3. **Determine Bond Pairs and Lone Pairs**:
- **For C2**:
- Divide total valence electrons by 8: 8 / 8 = 1 (1 bond pair).
- Remainder = 0, so lone pairs = 0.
- **For ClF3**:
- Divide total valence electrons by 8: 28 / 8 = 3 (3 bond pairs).
- Remainder = 4, so lone pairs = 4 / 2 = 2.
- **For SO3^2-**:
- Divide total valence electrons by 8: 26 / 8 = 3 (3 bond pairs).
- Remainder = 2, so lone pairs = 2 / 2 = 1.
- **For XeF4**:
- Divide total valence electrons by 8: 36 / 8 = 4 (4 bond pairs).
- Remainder = 4, so lone pairs = 4 / 2 = 2.

4. **Conclusion**:
- From our analysis:
- C2 has 0 lone pairs.
- ClF3 has 2 lone pairs.
- SO3^2- has 1 lone pair.
- XeF4 has 2 lone pairs.
- Therefore, the molecules that have two lone pairs of electrons on the central atom are **ClF3 and XeF4**.

### Final Answer:
The correct options are **B) ClF3 and D) XeF4**.