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When Zn reacts with conc HNO(3),then Zn(...

When Zn reacts with conc `HNO_(3),then Zn(NO_(3))_2 and NO_(2)` are formed , the reaction (s) involved in this process is/are

A

Redox reaction

B

Acid base reaction

C

Ion exchange reaction

D

None

Text Solution

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The correct Answer is:
To analyze the reaction between zinc (Zn) and concentrated nitric acid (HNO3), we can break down the process step by step. ### Step 1: Identify the Reactants and Products The reactants in this reaction are: - Zinc (Zn) - Concentrated Nitric Acid (HNO3) The products formed are: - Zinc Nitrate (Zn(NO3)2) - Nitrogen Dioxide (NO2) - Water (H2O) ### Step 2: Write the Balanced Chemical Equation The unbalanced chemical equation for the reaction is: \[ \text{Zn} + \text{HNO}_3 \rightarrow \text{Zn(NO}_3\text{)}_2 + \text{NO}_2 + \text{H}_2\text{O} \] To balance the equation, we find the coefficients that make the number of atoms of each element equal on both sides. The balanced equation is: \[ 4 \text{HNO}_3 + \text{Zn} \rightarrow \text{Zn(NO}_3\text{)}_2 + 2 \text{NO}_2 + 2 \text{H}_2\text{O} \] ### Step 3: Identify the Type of Reaction This reaction can be classified as: 1. **Redox Reaction**: Zinc is oxidized from an oxidation state of 0 to +2, while nitrogen in nitric acid is reduced from +5 in HNO3 to +4 in NO2. 2. **Acid-Base Reaction**: HNO3 acts as an acid, and the reaction produces a salt (Zn(NO3)2) and water (H2O). ### Step 4: Conclusion The reaction between zinc and concentrated nitric acid is both a redox reaction and an acid-base reaction. Therefore, the correct options are: - Redox Reaction - Acid-Base Reaction ### Final Answer The reaction involved in this process is: - Redox Reaction - Acid-Base Reaction
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Knowledge Check

  • Phenol reacts with conc. HNO_(3) in the presence of conc. H_(2)SO_(4) to give :

    A
    meta nitrophenol
    B
    ortho nitrophenol
    C
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    D
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  • What happens when methane reacts with conc. HNO_(3) at high temperature?

    A
    Nitromethane is formed
    B
    Methanol is formed.
    C
    `CO_(2) and H_(2)O` are formed.
    D
    CO and `H_(2)O` are formed.
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