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Strongly acidified solution of barium gi...

Strongly acidified solution of barium give a white precipitate with ……which did not dissolve even after large addition of water

A

Sodium phosphate

B

Sodium carbonate

C

Sodium salphate

D

Sodium chloride

Text Solution

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The correct Answer is:
To solve the question "Strongly acidified solution of barium gives a white precipitate with …… which did not dissolve even after large addition of water," we need to analyze the options provided and understand the chemistry involved. ### Step-by-Step Solution: 1. **Identify the Reaction**: We are looking for a substance that reacts with a strongly acidified solution of barium to form a white precipitate. Barium ions (Ba²⁺) are known to form precipitates with certain anions. 2. **Consider the Options**: The options given are: - A) Sodium phosphate (Na₃PO₄) - B) Sodium carbonate (Na₂CO₃) - C) Sodium sulphate (Na₂SO₄) - D) Sodium chloride (NaCl) 3. **Analyze Each Option**: - **Sodium phosphate (Na₃PO₄)**: When reacted with barium ions, it forms barium phosphate (Ba₃(PO₄)₂), which is a white precipitate but is soluble in strong acids. - **Sodium carbonate (Na₂CO₃)**: This would produce barium carbonate (BaCO₃), which is a white precipitate but is also soluble in acidic conditions. - **Sodium sulphate (Na₂SO₄)**: This reacts with barium ions to form barium sulphate (BaSO₄), which is a white precipitate that is insoluble in water and even in acidic solutions. - **Sodium chloride (NaCl)**: This does not form any precipitate with barium ions. 4. **Conclusion**: The only option that forms a white precipitate that is insoluble in water and even in an acidic medium is sodium sulphate (Na₂SO₄), which produces barium sulphate (BaSO₄). 5. **Final Answer**: Therefore, the correct answer is **C) Sodium sulphate**.
To solve the question "Strongly acidified solution of barium gives a white precipitate with …… which did not dissolve even after large addition of water," we need to analyze the options provided and understand the chemistry involved. ### Step-by-Step Solution: 1. **Identify the Reaction**: We are looking for a substance that reacts with a strongly acidified solution of barium to form a white precipitate. Barium ions (Ba²⁺) are known to form precipitates with certain anions. 2. **Consider the Options**: The options given are: - A) Sodium phosphate (Na₃PO₄) ...
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