Ferric alum is the indicator in the titration of `Ag^(o+)` with `SCN^(Θ)` when (a)_____colour appears at the end point .

Answer

To solve the question regarding the color that appears at the endpoint of the titration of `Ag^(+)` with `SCN^(-)` using ferric alum as an indicator, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Reaction**:
- In this titration, silver ions (`Ag^(+)`) react with thiocyanate ions (`SCN^(-)`) to form a complex. The reaction can be represented as:
\[ Ag^{+} + SCN^{-} \rightarrow [Ag(SCN)]^{+} \]
- As more `SCN^(-)` is added, the complex can further react to form a more stable complex.

2. **Formation of the Complex**:
- The complex formed is `[Ag(SCN)]^{+}`, which can further react with ferric ions (`Fe^{3+}`) from ferric alum to form a red-colored complex:
\[ [Ag(SCN)]^{+} + Fe^{3+} \rightarrow [Fe(SCN)]^{2+} \text{ (red complex)} \]
- This red complex is responsible for the color change observed at the endpoint of the titration.

3. **Identifying the Endpoint Color**:
- The endpoint of the titration is indicated by the appearance of a red color due to the formation of the iron(III) thiocyanate complex, `[Fe(SCN)]^{2+}`.

4. **Conclusion**:
- Therefore, the blank in the question can be filled with "red color".

### Final Answer:
Ferric alum is the indicator in the titration of `Ag^(+)` with `SCN^(-)` when **red color** appears at the endpoint.

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