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A: Alkene A(Me2 C = CMe2) is more stable...

A: Alkene `A(Me_2 C = CMe_2)` is more stable than alkene `B(Et_2 C = Cet_2)`
R: Baker-Nathan effect.

A

If both (A) and ( R) are true and ( R) is the correct explanation of (A).

B

If both (A) and ( R) are true but ( R) is not correct explanation of (A).

C

If (A) is true but ( R) is false.

D

If (A) is false but ( R) if true.

Text Solution

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The correct Answer is:
To solve the question regarding the stability of alkenes A and B, we will analyze the structures and apply the concept of hyperconjugation, also known as the Baker-Nathan effect. ### Step-by-Step Solution: 1. **Identify the Structures of Alkenes A and B**: - Alkene A: \( \text{Me}_2C = C\text{Me}_2 \) (2,3-dimethylbutene) - Alkene B: \( \text{Et}_2C = C\text{Et}_2 \) (2,3-diethylbutene) 2. **Draw the Structures**: - Alkene A has two methyl groups attached to each carbon of the double bond. - Alkene B has two ethyl groups attached to each carbon of the double bond. 3. **Count the Alpha Hydrogens**: - Alpha hydrogens are the hydrogens attached to the carbons adjacent to the double bond. - For Alkene A: - Each carbon in the double bond has 6 alpha hydrogens (3 from each methyl group). - Total alpha hydrogens in A = 12. - For Alkene B: - Each carbon in the double bond has 4 alpha hydrogens (2 from each ethyl group). - Total alpha hydrogens in B = 8. 4. **Analyze Hyperconjugation**: - Hyperconjugation refers to the stabilizing interaction that results from the overlap of a sigma bond orbital with an empty p-orbital or a pi-bond orbital. - The more alpha hydrogens present, the greater the hyperconjugation effect, leading to increased stability of the alkene. 5. **Compare Stability**: - Alkene A has more alpha hydrogens (12) compared to Alkene B (8). - Therefore, Alkene A is more stable due to a greater extent of hyperconjugation. 6. **Conclusion**: - The assertion (A is more stable than B) is true. - The reason (Baker-Nathan effect) is also true and explains why A is more stable than B. ### Final Answer: Both the assertion and reason are true, and the reason is the correct explanation for the assertion.

To solve the question regarding the stability of alkenes A and B, we will analyze the structures and apply the concept of hyperconjugation, also known as the Baker-Nathan effect. ### Step-by-Step Solution: 1. **Identify the Structures of Alkenes A and B**: - Alkene A: \( \text{Me}_2C = C\text{Me}_2 \) (2,3-dimethylbutene) - Alkene B: \( \text{Et}_2C = C\text{Et}_2 \) (2,3-diethylbutene) ...
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