(A) `A(C_(7)H_(14)) overset(O_(3)//Red)(rarr)B(C_(3)H_(6)O)+C`
(B) Gives positive Tollens test but negative iodform test.
(C ) Give negative Tollens test but positive iodoform test.
The compound (A) is:

Options

A. a.
B. b.
C. c.
D. d.Both `(a)` and `(b)`

Explanation

To solve the problem step by step, we will analyze the information given and apply our knowledge of organic chemistry, particularly focusing on the reactions involving ozonolysis and the tests for aldehydes and ketones.

### Step 1: Identify the structure of compound A
Given that compound A has the molecular formula \( C_7H_{14} \), we can deduce that it is an alkene because it has a degree of unsaturation (double bond). The simplest structure for a heptene (an alkene with 7 carbon atoms) is 1-heptene or 2-heptene.

**Hint:** Remember that alkenes have at least one double bond and can be represented as \( C_nH_{2n} \).

### Step 2: Understand the ozonolysis reaction
Ozonolysis of alkenes typically breaks the double bond and forms carbonyl compounds (aldehydes and/or ketones). In this case, we know that compound A will yield two products: compound B and compound C.

**Hint:** Ozonolysis of an alkene results in the formation of carbonyl compounds, which can be either aldehydes or ketones.

### Step 3: Analyze the properties of compounds B and C
From the problem, we know:
- Compound B (C3H6O) gives a positive Tollens test and a negative iodoform test.
- Compound C gives a negative Tollens test but a positive iodoform test.

**Hint:** Recall that Tollens test is positive for aldehydes and negative for ketones, while the iodoform test is positive for methyl ketones and some secondary alcohols.

### Step 4: Determine the identities of compounds B and C
Since compound B gives a positive Tollens test, it must be an aldehyde. The negative iodoform test indicates that it is not a methyl ketone. Therefore, compound B is likely propanal (C3H6O).

For compound C, which gives a negative Tollens test and a positive iodoform test, it must be a ketone. The only ketone that fits this description and has the molecular formula C4H8O is butanone.

**Hint:** Use the properties of the tests to deduce the functional groups of the compounds.

### Step 5: Conclude the structure of compound A
Since compound A is an alkene that yields propanal and butanone upon ozonolysis, we can deduce that the structure of compound A must be 2-heptene. This structure allows for the formation of one aldehyde (propanal) and one ketone (butanone) upon ozonolysis.

**Hint:** Consider the positions of the double bond in alkenes to determine the products formed during ozonolysis.

### Final Answer
The compound A is **2-heptene**.