Home
Class 12
CHEMISTRY
The first steps of SN^(1) and SN^(2) rec...

The first steps of `SN^(1)` and `SN^(2)` recatiosns are, respectively

A

Both exothermic

B

Both endotherimic

C

Endothermic and exothermic

D

Exothermic and endothermic

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the first steps of SN1 and SN2 reactions, we need to understand the mechanisms of these two types of nucleophilic substitution reactions. ### Step-by-Step Solution: 1. **Understanding SN1 Mechanism:** - The SN1 (Substitution Nucleophilic Unimolecular) reaction involves two steps: - **Step 1:** The leaving group departs, forming a carbocation intermediate. This step requires energy to break the bond between the carbon and the leaving group, making it **endothermic**. - **Step 2:** The nucleophile attacks the carbocation, resulting in the formation of the product. This step releases energy, making it **exothermic**. 2. **Understanding SN2 Mechanism:** - The SN2 (Substitution Nucleophilic Bimolecular) reaction involves a single concerted step: - The nucleophile attacks the carbon atom simultaneously as the leaving group departs. This step is typically **exothermic** because it involves the formation of a new bond while breaking an old bond. 3. **Summarizing the Steps:** - For **SN1**: - First step: **Endothermic** (formation of carbocation) - Second step: **Exothermic** (nucleophile attacks) - For **SN2**: - Only step: **Exothermic** (concerted reaction) 4. **Conclusion:** - The first step of SN1 is endothermic, and the first step of SN2 is exothermic. Therefore, the correct answer to the question is that the first steps of SN1 and SN2 reactions are **endothermic and exothermic**, respectively. ### Final Answer: The first steps of SN1 and SN2 reactions are **endothermic and exothermic**, respectively. ---

To solve the question regarding the first steps of SN1 and SN2 reactions, we need to understand the mechanisms of these two types of nucleophilic substitution reactions. ### Step-by-Step Solution: 1. **Understanding SN1 Mechanism:** - The SN1 (Substitution Nucleophilic Unimolecular) reaction involves two steps: - **Step 1:** The leaving group departs, forming a carbocation intermediate. This step requires energy to break the bond between the carbon and the leaving group, making it **endothermic**. - **Step 2:** The nucleophile attacks the carbocation, resulting in the formation of the product. This step releases energy, making it **exothermic**. ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • AROMATIC COMPOUNDS AND ALKYL AND ARYL HALIDES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Multiple Correct Answers Type|15 Videos
  • AROMATIC COMPOUNDS AND ALKYL AND ARYL HALIDES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Single Correct Answer Type|28 Videos
  • AROMATIC COMPOUNDS AND ALKYL AND ARYL HALIDES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Linked Compreshension Type|11 Videos
  • APPENDIX INORGANIC VOLUME 2

    CENGAGE CHEMISTRY ENGLISH|Exercise Short Answer Type|179 Videos
  • BIOMOLECULES

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Analytical And Descriptive)|8 Videos

Similar Questions

Explore conceptually related problems

Which of the following halides will be most reactive in SN^(2) reaction and SN^(1) reaction respectively?

SN^(1) reaction is feasable in-

Let S_n denote the sum of first n terms of a G.P. whose first term and common ratio are a and r respectively. On the basis of above information answer the following question: The sum of product of first n terms of the G.P. taken two at a time in (A) (r+1)/r S_nS_(n-1) (B) r/(r+1)S_n^2 (C) r/(r+1)S_nS_(n-1) (D) none of these

SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walken inversion by SN^(2) mechanism. The presence of hero group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will give SN^(1) reaction?

SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walken inversion by SN^(2) mechanism. The presence of hero group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will give SN^(2) mechanism?

SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walden inversion by SN^(2) mechanism. The presence of hetro group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will gives SN^(2) mechanism gt

Let S_n denote the sum of first n terms of a G.P. whose first term and common ratio are a and r respectively. On the basis of above information answer the following question: S_1+S_2+S_3+..+S_n= (A) (na)/(1-r)-(ar(1-r^n))/((1-r)^2 (B) (na)/(1-r)-(ar(1+r^n))/((1+r)^2 (C) (na)/(1-r)-(a(1-r^n))/((1-r)^2 (D) none of these

SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walken inversion by SN^(2) mechanism. The presence of hero group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will give Walden inversion ?

Predicrt the order of reactivity of the following compounds in SN^(1) and SN^(2) reactions.

The most reactive towards SN^(1) is: