Statement-1 : Bond dissociation energy of `F_(2)` is more than `Cl_(2)`.
Statement-2 : Due to smaller size of fluorine there are greater electron repulsions between the F atoms than Cl atoms.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To solve the question, we will analyze both statements provided regarding the bond dissociation energy of \( F_2 \) and \( Cl_2 \).

### Step-by-Step Solution:

1. **Understanding Bond Dissociation Energy**:
- Bond dissociation energy (BDE) is the energy required to break a bond between two atoms in a molecule. A higher BDE indicates a stronger bond.

2. **Comparing \( F_2 \) and \( Cl_2 \)**:
- \( F_2 \) (fluorine) and \( Cl_2 \) (chlorine) are diatomic molecules consisting of the same type of atoms.
- Fluorine is in the second period of the periodic table, while chlorine is in the third period. This means that fluorine atoms are smaller than chlorine atoms.

3. **Analyzing Statement 1**:
- Statement 1 claims that the bond dissociation energy of \( F_2 \) is greater than that of \( Cl_2 \).
- However, due to the smaller size of the fluorine atoms, there are significant electron-electron repulsions between the lone pairs of electrons on each fluorine atom.
- This repulsion weakens the bond in \( F_2 \), resulting in a lower bond dissociation energy compared to \( Cl_2 \).

4. **Analyzing Statement 2**:
- Statement 2 states that due to the smaller size of fluorine, there are greater electron repulsions between the \( F \) atoms than between the \( Cl \) atoms.
- This statement is true because the closer proximity of the electrons in smaller atoms leads to increased repulsion.

5. **Conclusion**:
- Therefore, Statement 1 is **false** (the bond dissociation energy of \( Cl_2 \) is greater than that of \( F_2 \)), and Statement 2 is **true** (greater electron repulsions exist in \( F_2 \) due to its smaller size).

### Final Answer:
- Statement 1 is false, and Statement 2 is true.