For `Ag^(+)` metal ion, correct sequence regarding ligand strength is

Options

A. `F^(-) gt Cl^(-) gt Br^(-) gt I^(-)`
B. `I^(-) gt Br ^(-) gt Cl^(-) gt F^(-)`
C. `Cl^(-) gt Br^(-) gt F^(-) gt I^(-)`
D. `F^(-) gt Br^(-) gt I^(-) gt Cl^(-)`

Answer

To determine the correct sequence regarding ligand strength for the silver ion \( Ag^+ \), we need to analyze the halide ions and their ability to stabilize the \( Ag^+ \) ion based on their size and charge density.

### Step-by-Step Solution:

1. **Identify the Ligands**: The ligands in question are halide ions: \( I^- \), \( Br^- \), \( Cl^- \), and \( F^- \).

2. **Understand Ligand Strength**: Ligand strength can be influenced by the size of the ligand and its ability to stabilize the metal ion. Larger ligands can stabilize larger metal ions better due to their size and lower charge density.

3. **Size of Halide Ions**: The size of the halide ions increases as follows:
- \( F^- \) (smallest)
- \( Cl^- \)
- \( Br^- \)
- \( I^- \) (largest)

4. **Stabilization of \( Ag^+ \)**: Since \( Ag^+ \) is a relatively large ion, it will be stabilized more effectively by larger ligands. Therefore, the stabilization order will be:
- \( I^- \) (most stabilizing due to its large size)
- \( Br^- \)
- \( Cl^- \)
- \( F^- \) (least stabilizing due to its small size)

5. **Correct Sequence**: Based on the analysis, the correct sequence regarding ligand strength for \( Ag^+ \) is:
\[ I^- > Br^- > Cl^- > F^- \]

### Final Answer:
The correct sequence regarding ligand strength for \( Ag^+ \) is \( I^- > Br^- > Cl^- > F^- \).