Statement-1 : First Ionisation energy of beryllium is more than boron.
Statement-2 : In boron, 2p orbital is fully filled, whereas, in beryllium, it is not fully filled.

Options

A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False
D. Statement-1 is False, Statement-2 is True

Answer

To solve the question, we need to analyze both statements regarding the first ionization energy of beryllium and boron, as well as the electronic configurations of these elements.

### Step-by-Step Solution:

1. **Understanding Ionization Energy**:
- Ionization energy (IE) is the energy required to remove an electron from an isolated gaseous atom. The first ionization energy (IE1) is the energy needed to remove the outermost electron.

2. **Electronic Configuration of Beryllium and Boron**:
- Beryllium (Be) has an atomic number of 4. Its electronic configuration is:
- 1s² 2s² 2p⁰
- Boron (B) has an atomic number of 5. Its electronic configuration is:
- 1s² 2s² 2p¹

3. **Analyzing Statement 1**:
- Statement 1 claims that the first ionization energy of beryllium is more than that of boron.
- In beryllium, the outermost electrons are in the 2s orbital (2s²), which is fully filled and stable. Removing one of these electrons requires more energy.
- In boron, the outermost electron is in the 2p orbital (2p¹). Removing this electron is easier because after its removal, boron achieves a stable configuration of 1s² 2s².
- Therefore, **Statement 1 is true**: The first ionization energy of beryllium is indeed greater than that of boron.

4. **Analyzing Statement 2**:
- Statement 2 claims that in boron, the 2p orbital is fully filled, whereas in beryllium, it is not fully filled.
- In reality, the 2p orbital in boron has one electron (2p¹), meaning it is not fully filled. The 2p orbital in beryllium is empty (2p⁰).
- Therefore, **Statement 2 is false**: The 2p orbital in boron is not fully filled.

5. **Conclusion**:
- Based on the analysis, we conclude that:
- Statement 1 is true.
- Statement 2 is false.
- The correct option is: **Statement 1 is true, Statement 2 is false**.

### Final Answer:
- **Option 3**: Statement 1 is true, Statement 2 is false.