Balance the equation by lon-electron method
`Cr_(2)O_(7)^(2-) + Fe^(2+) to Fe^(3+) +Cr^(3+)`(In acidic medium)

Explanation

To balance the redox reaction \( \text{Cr}_2\text{O}_7^{2-} + \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + \text{Cr}^{3+} \) in acidic medium using the ion-electron method, follow these steps:

### Step 1: Assign Oxidation States
- **Chromium in \(\text{Cr}_2\text{O}_7^{2-}\)**:
- Let the oxidation state of Cr be \( x \).
- The equation becomes \( 2x + 7(-2) = -2 \).
- Solving gives \( 2x - 14 = -2 \) → \( 2x = 12 \) → \( x = +6 \).
- **Iron in \(\text{Fe}^{2+}\)**: +2
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