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Statement-1: H(2)O(2) is more polar than...

Statement-1: `H_(2)O_(2)` is more polar than `H_(2)O`
Statement-2: `D_(2)O` has higher boiling point than `H_(2)O`
Statement-3: `H_(2)` bond bond energy is less than `D_(2)`.

A

TTT

B

TTF

C

TFF

D

FFT

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement one by one and determine whether they are true or false. ### Step 1: Evaluate Statement 1 **Statement 1:** `H₂O₂` is more polar than `H₂O`. - **Analysis:** - `H₂O` (water) has a bent molecular geometry due to the two lone pairs on the oxygen atom, resulting in a significant dipole moment. - `H₂O₂` (hydrogen peroxide) has a skewed (or non-planar) structure, which also contributes to its polarity. The presence of oxygen atoms with lone pairs creates a higher dipole moment compared to water. - Therefore, `H₂O₂` is indeed more polar than `H₂O`. - **Conclusion:** This statement is **True**. ### Step 2: Evaluate Statement 2 **Statement 2:** `D₂O` has a higher boiling point than `H₂O`. - **Analysis:** - `D₂O` (heavy water) contains deuterium, which has a greater atomic mass than protium (the hydrogen in `H₂O`). - The boiling point of a substance is influenced by its molecular weight; heavier molecules generally have higher boiling points due to stronger van der Waals forces. - Since `D₂O` has a higher molecular weight than `H₂O`, it will have a higher boiling point. - **Conclusion:** This statement is **True**. ### Step 3: Evaluate Statement 3 **Statement 3:** `H₂` bond energy is less than `D₂`. - **Analysis:** - The bond dissociation energy is the energy required to break a bond. - The bond energy of `H₂` (hydrogen) is less than that of `D₂` (deuterium) because deuterium has a higher mass, and the bond is stronger due to the reduced zero-point energy of the heavier isotope. - Therefore, it requires more energy to break the bond in `D₂` compared to `H₂`. - **Conclusion:** This statement is **True**. ### Final Conclusion All three statements are true. Therefore, the answer to the question is that all statements are correct. ### Summary of Answers: - Statement 1: True - Statement 2: True - Statement 3: True
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Knowledge Check

  • Statement-1 : Boiling point of H_(2)O is more than HF . and Statement-2 : Intermolecular hydrogen bonding in HF is stronger than H_(2)O .

    A
    H - F has highest van der Waals forces and dipole moment.
    B
    H - F has highest London forces.
    C
    H - F has highest dipole moment hence has dipole - dipole , London forces and hydrogen bonding.
    D
    H - F has strong intermolecular interactions like dipole - induced dipole.
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