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If diborane each boron has three electro...

If diborane each boron has three electrons bonds around each B atom and form

A

Two

B

Three

C

Four

D

Five

Text Solution

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The correct Answer is:
To solve the question regarding the number of bonds around each boron atom in diborane (B2H6), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Structure of Diborane**: - Diborane consists of two boron (B) atoms and six hydrogen (H) atoms. The formula is B2H6. - Each boron atom in diborane is bonded to three hydrogen atoms and participates in bridging bonds with the other boron atom. 2. **Electronic Configuration of Boron**: - The electronic configuration of boron is 1s² 2s² 2p¹. This means that boron has three valence electrons. 3. **Hybridization in Boron**: - In diborane, boron undergoes hybridization. The 1s and 2p orbitals of boron can be excited to form four sp³ hybrid orbitals (one 2s and three 2p orbitals). - However, in diborane, only three of these sp³ hybrid orbitals are used to form bonds with hydrogen atoms. 4. **Formation of Bonds**: - Each boron atom forms three covalent bonds with three hydrogen atoms using its three sp³ hybrid orbitals. - Additionally, there is a unique bonding situation in diborane where the two boron atoms share a pair of electrons through a bridging bond involving a hydrogen atom. This is known as a 3-center 2-electron bond. 5. **Counting the Bonds**: - Each boron atom is involved in three B-H bonds (one with each hydrogen) and one bridging bond with the other boron atom. - Therefore, each boron atom effectively has four bonds around it: three from the hydrogen atoms and one bridging bond with the other boron atom. 6. **Conclusion**: - Thus, the number of bonds around each boron atom in diborane is **4**. ### Final Answer: The correct answer is **4**. ---
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Knowledge Check

  • In diborane, banana bond is formed between

    A
    2 electrons, 3 atoms
    B
    2 electrons, 1 atom
    C
    2 electrons, 2 atoms
    D
    1 electron, 2 atoms.

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    Borane is an electron deficient compound. It has only six valence eletons, so the boron atom lacks an octet. Acquiring an octet is the driving force for the unusual bonding structure found in boron compounds. As an electron deficient compound, BH_(3) is a strong electrophile, capable of adding to a double bond. This hydroboration of double bond is though to oC Cur in one step, with the boron atom adding to the less highly substituted end of the double bond. In transition state, the boron atom withdraws electrons from the pi bond and the carbon at theother end of the double bond acquires a partial positive charge. This positive charge is more stable on the more highly subsituted carbon atom. The second step is the oxidation of boron atom, removing it from carbon and replacing it with hydroxyl group by using H_(2)O_(2)//OH^(bar(..)) . The simultaneous addition of boron and hydrogen to the double bond leads to a syn addition. Oxidation of the trialkyl borane replaces boron with a hydroxyl group in the same stereochemical position. Thus, hydroboration of alkenen is an example of steropecific reaction, in which different steroisomers of starting compounds react to give different steroisomers of the product. Y is :

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