STATEMENT - 1 : `NaNO_(2)` on treatment with dil. HCl gives brown coloured gas directly.
STATEMENT -- 2 : `[Fe(CN)_5NO]^(-2)` is used for the detection of of `S^(-2)`.
STATEMENT - 3 : Precipitate of Agl are of yellow colour

Options

A. FTF
B. FTT
C. TTF
D. TTT

Answer

To analyze the three statements provided in the question, we will evaluate each statement step by step.

### Step 1: Evaluate Statement 1
**Statement 1:** "NaNO₂ on treatment with dilute HCl gives brown colored gas directly."

**Analysis:**
When sodium nitrite (NaNO₂) reacts with dilute hydrochloric acid (HCl), the reaction produces nitrous acid (HNO₂) and sodium chloride (NaCl). The reaction can be represented as:
\[ \text{NaNO}_2 + \text{HCl} \rightarrow \text{NaCl} + \text{HNO}_2 \]

The nitrous acid (HNO₂) can decompose to produce nitrogen dioxide (NO₂), which is a brown gas, but this decomposition does not happen directly in the presence of dilute HCl. Instead, the direct product of the reaction is HNO₂, which is not brown. Therefore, the statement is **false**.

### Step 2: Evaluate Statement 2
**Statement 2:** "[Fe(CN)₅NO]²⁻ is used for the detection of S²⁻."

**Analysis:**
This statement refers to the use of sodium nitroprusside (Na₂[Fe(CN)₅NO]) in the detection of sulfide ions (S²⁻). When sulfide ions react with sodium nitroprusside, they form a complex that is purple or violet in color. The reaction can be summarized as:
\[ \text{Na}_2\text{Fe(CN)}_5\text{NO} + \text{Na}_2\text{S} \rightarrow \text{Na}_4\text{Fe(CN)}_5\text{NOS} \]

The formation of this purple complex indicates the presence of sulfide ions. Therefore, this statement is **true**.

### Step 3: Evaluate Statement 3
**Statement 3:** "Precipitate of AgI are of yellow color."

**Analysis:**
Silver iodide (AgI) is indeed known to form a yellow precipitate when silver nitrate (AgNO₃) reacts with sodium iodide (NaI). The reaction can be represented as:
\[ \text{NaI} + \text{AgNO}_3 \rightarrow \text{AgI (s)} + \text{NaNO}_3 \]

The precipitate of AgI is yellow, confirming that this statement is also **true**.

### Conclusion
Based on the evaluations:
- Statement 1: False
- Statement 2: True
- Statement 3: True

Thus, the answer to the question is **FTT** (False, True, True).

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