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500 ml CuSO(4) solution was electrolysed...

500 ml `CuSO_(4)` solution was electrolysed using a current of 2 amp (efficiency =75%) for 60 min calculate the pH of solution at the end of electrolysis (Assume initial pH=7)

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To solve the problem step by step, we will follow the process of calculating the amount of charge passed, the moles of sulfuric acid produced, and finally, the pH of the solution. ### Step 1: Calculate the total charge passed during electrolysis Given: - Current (I) = 2 A - Time (t) = 60 minutes First, convert the time from minutes to seconds: ...
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