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An alekene on ozonolysis and hydrolysis ...

An alekene on ozonolysis and hydrolysis in presence of zinc dust produced one molecule of `CH_(3)CHO` and one molecule of HCHO. What is the alkene used in the reaction?

A

`CH_(3)-CH=CH_(2)`

B

`CH_(3)-CH=CH-CH_(3)`

C

`CH_(3)-underset(CH_(3))underset(|)(CH)=CH_(2)`

D

`CH_(3)-CH_(2)-CH=CH`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the alkene that produces one molecule of CH₃CHO (acetaldehyde) and one molecule of HCHO (formaldehyde) upon ozonolysis and hydrolysis in the presence of zinc dust, we can follow these steps: ### Step 1: Understand the Reaction Ozonolysis is a reaction that cleaves carbon-carbon double bonds (alkenes) and introduces oxygen atoms. In this case, we are dealing with reductive ozonolysis, which uses zinc dust and water. The products in this scenario are aldehydes. ### Step 2: Identify the Products The products given are: - CH₃CHO (acetaldehyde) - HCHO (formaldehyde) ### Step 3: Analyze the Products From the products, we can deduce that: - One molecule of CH₃CHO indicates that one of the fragments must have a carbon chain that can yield this aldehyde. - The other molecule, HCHO, suggests that the other fragment is a simple aldehyde. ### Step 4: Consider Possible Alkenes We need to find an alkene that, when cleaved, produces these two specific aldehydes. Let's consider the alkene: - **Propene (CH₃-CH=CH₂)** ### Step 5: Perform Ozonolysis on Propene When propene undergoes ozonolysis: 1. The double bond between the second and third carbon atoms is cleaved. 2. This results in the formation of: - CH₃CHO (from the CH₃-CH part) - HCHO (from the CH₂ part) ### Step 6: Conclusion Thus, the alkene that produces one molecule of CH₃CHO and one molecule of HCHO upon ozonolysis and hydrolysis in the presence of zinc dust is **Propene (CH₃-CH=CH₂)**. ### Summary of the Solution Steps: 1. Understand the ozonolysis reaction and its products. 2. Identify the products as CH₃CHO and HCHO. 3. Analyze the structure of the products to deduce the possible alkene. 4. Test the alkene (Propene) to see if it produces the desired products. 5. Conclude that Propene is the alkene used.
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AAKASH INSTITUTE ENGLISH-HYDROCARBONS-ASSIGNMENT SECTION-A COMPETITION LEVEL DIFFER BY
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  16. Which among the following is a meta directing group?

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