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Statement -1 : Rate of S(N)1 reaction ...

Statement -1 : Rate of `S_(N)1` reaction is faster than that of `S_(N)2` reaction
Statement -2 : `S_(N)2` reaction is favoured by polar aprotic solvent
Statement -3 : `S_(N)1` reaction involves racemization

A

TTT

B

FFT

C

FTT

D

TFT

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement one by one and determine their validity based on the principles of nucleophilic substitution reactions (SN1 and SN2). ### Step-by-Step Solution: **Step 1: Analyze Statement 1** - **Statement 1**: The rate of SN1 reaction is faster than that of SN2 reaction. - **Explanation**: SN1 reactions involve the formation of a carbocation intermediate, which is a key factor in determining the rate of the reaction. The rate of an SN1 reaction depends solely on the concentration of the substrate, as the rate-determining step is the formation of the carbocation. In contrast, SN2 reactions involve a single concerted step where the nucleophile attacks the substrate simultaneously as the leaving group departs. Generally, for tertiary substrates, SN1 reactions are faster than SN2 due to the stability of the carbocation formed. Thus, this statement is **true**. **Step 2: Analyze Statement 2** - **Statement 2**: SN2 reaction is favored by polar aprotic solvent. - **Explanation**: Polar aprotic solvents do not have hydrogen bonding capabilities that can stabilize the nucleophile. These solvents allow the nucleophile to remain more reactive, which is essential for the bimolecular nucleophilic substitution (SN2) mechanism. In contrast, SN1 reactions are favored by polar protic solvents, which stabilize the carbocation intermediate. Therefore, this statement is also **true**. **Step 3: Analyze Statement 3** - **Statement 3**: SN1 reaction involves racemization. - **Explanation**: In an SN1 reaction, the formation of a planar carbocation allows the nucleophile to attack from either side of the carbocation. This leads to the formation of both enantiomers, resulting in racemization. Thus, this statement is **true**. ### Conclusion: All three statements are true based on the principles of SN1 and SN2 reactions. ### Final Answer: - **All statements are true.**
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Similar Questions

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In S_(N)1 reaction, the first step involves the formation of:

In the following S_(N)2 reaction

Knowledge Check

  • Rate of S_(N^2) reaction is :

    A
    `(B) gt (A) gt (C)`
    B
    `(C) gt (A) gt (B)`
    C
    `(A) gt (B) gt (C)`
    D
    `(A) gt (C) gt (B)`
  • S_(N^1) reaction is fastest in

    A
    `CH_3CH_2Br`
    B
    `CH_3-underset(Cl)underset(|)(CH)-CH_3`
    C
    `CH_3-underset(CH_3)underset(|)overset(CH_3)underset(|)C-Cl`
    D
    `CH_3-underset(CH_3)underset(|)underset(CH_2)underset(|)(CH)-Cl`
  • S_(N^1) and S_(N^2) reactions are

    A
    Both stereospecific
    B
    Both stereoselective
    C
    Stereoselective and stereospecific respectively
    D
    Stereospecific and stereoselective respectively
  • Similar Questions

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    Which of the following solvent is suitable for S_(N)1 reaction ?

    In an S_(N)1 reaction on chiral centres, there is

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    Which one is the most reactive towards S_(N)1 reaction ?

    An S_(N^2) reaction occurs through the formation of a