Which of the following compounds on hydrolysis yields a carboxylic acid?

Options

A.
B.
C.
D.

Answer

To determine which of the given compounds yields a carboxylic acid upon hydrolysis, let's analyze each option step by step.

### Step-by-Step Solution:

1. **Identify the Compounds**: We have four compounds to analyze. Let's denote them as Compound 1, Compound 2, Compound 3, and Compound 4.

2. **Analyze Compound 1 (Cyanide)**:
- **Hydrolysis Reaction**: When cyanide (R-CN) undergoes hydrolysis in the presence of an acid, it forms a carboxylic acid (R-COOH).
- **Conclusion**: Compound 1 yields a carboxylic acid.

3. **Analyze Compound 2 (Amide)**:
- **Structure**: The compound is a phenyl amide (C6H5-NH-CO-C6H5).
- **Hydrolysis Reaction**: When this amide undergoes hydrolysis, it reacts with water. The hydroxide ion (OH-) attacks the carbonyl carbon, leading to the formation of benzoic acid (C6H5-COOH) and an amine (C6H5-NH2).
- **Conclusion**: Compound 2 yields a carboxylic acid.

4. **Analyze Compound 3 (Acyl Halide)**:
- **Structure**: The compound is an acyl chloride (R-COCl).
- **Hydrolysis Reaction**: During hydrolysis, the hydroxide ion (OH-) attacks the carbonyl carbon, displacing the chloride ion (Cl-) and forming a carboxylic acid (R-COOH).
- **Conclusion**: Compound 3 yields a carboxylic acid.

5. **Analyze Compound 4 (Anhydride)**:
- **Structure**: The compound is an anhydride (R-CO-O-CO-R).
- **Hydrolysis Reaction**: Hydrolysis of an anhydride results in the formation of two moles of the corresponding carboxylic acid (R-COOH).
- **Conclusion**: Compound 4 yields a carboxylic acid.

### Final Conclusion:
All four compounds (1, 2, 3, and 4) yield a carboxylic acid upon hydrolysis.

### Answer:
1, 2, 3, and 4 (All options are correct).

---