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Two balls, each of radius R, equal mass ...

Two balls, each of radius R, equal mass and density are placed in contact, then the force of gravitation between them is proportional to

A

R

B

`R^(2)`

C

`R^(-4)`

D

`R^(4)`

Text Solution

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The correct Answer is:
To solve the problem of finding the gravitational force between two balls placed in contact, we can follow these steps: ### Step 1: Understand the setup We have two balls, each with a radius \( R \), equal mass \( m \), and equal density \( \rho \). They are in contact, meaning the distance between their centers is \( 2R \). ### Step 2: Write the formula for gravitational force The gravitational force \( F \) between two masses is given by Newton's law of gravitation: \[ F = \frac{G m_1 m_2}{r^2} \] where \( G \) is the gravitational constant, \( m_1 \) and \( m_2 \) are the masses of the two balls, and \( r \) is the distance between their centers. ### Step 3: Substitute the values Since both balls have equal mass \( m \), we can substitute \( m_1 = m_2 = m \) and \( r = 2R \): \[ F = \frac{G m^2}{(2R)^2} = \frac{G m^2}{4R^2} \] ### Step 4: Express mass in terms of density and volume The mass \( m \) of each ball can be expressed in terms of its density \( \rho \) and volume \( V \): \[ m = \rho V \] The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi R^3 \] Thus, substituting for \( m \): \[ m = \rho \left(\frac{4}{3} \pi R^3\right) \] ### Step 5: Substitute mass back into the force equation Now, substituting \( m \) into the gravitational force equation: \[ F = \frac{G \left(\rho \left(\frac{4}{3} \pi R^3\right)\right)^2}{4R^2} \] \[ = \frac{G \left(\rho^2 \left(\frac{16}{9} \pi^2 R^6\right)\right)}{4R^2} \] \[ = \frac{G \cdot 16 \pi^2 \rho^2 R^6}{36 R^2} \] ### Step 6: Simplify the expression Now, simplify the expression: \[ F = \frac{16 G \pi^2 \rho^2 R^4}{36} \] This shows that the force \( F \) is proportional to \( R^4 \). ### Conclusion Thus, the gravitational force between the two balls is proportional to \( R^4 \). ### Final Answer The force of gravitation between the two balls is proportional to \( R^4 \). ---
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Knowledge Check

  • Two identical spheres of radius R made of the same material are kept at a distance d apart. Then the gravitational attraction between them is proportional to

    A
    `d^(-2)`
    B
    `d^(2)`
    C
    `d^(4)`
    D
    `d`
  • The gravitational force between two bodies is :

    A
    always repulsive
    B
    always attractive
    C
    attractive only at large distances
    D
    repulsive only at large distances.
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