Home
Class 12
PHYSICS
Maxwell's equation oint vecB * d vecs = ...

Maxwell's equation `oint vecB * d vecs = 0` says

A

a. Monopole can exist

B

b. Only dipole can exist

C

c. Magnetic field lines are closed loop

D

d. Net flux through surface is zero

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding Maxwell's equation `oint vecB * d vecs = 0`, we need to analyze what this equation implies about magnetic fields and their properties. ### Step-by-Step Solution: 1. **Understanding the Equation**: The equation `oint vecB * d vecs = 0` represents a line integral of the magnetic field vector `vecB` around a closed loop. This means that when we take the integral of the magnetic field along a closed path, the result is zero. **Hint**: Recall that a line integral around a closed loop gives information about the circulation of a vector field. 2. **Implication of the Equation**: The fact that this integral equals zero indicates that there are no net magnetic field lines passing through the loop. This is a fundamental property of magnetic fields, which suggests that magnetic field lines do not begin or end at any point (unlike electric field lines). **Hint**: Consider the nature of magnetic field lines and how they differ from electric field lines. 3. **Monopoles vs. Dipoles**: The equation implies that magnetic monopoles (isolated north or south poles) cannot exist. If they did, we would expect to see a net flux through the surface formed by the closed loop, which contradicts the equation. **Hint**: Think about how monopoles would affect the magnetic field lines and the implications for the line integral. 4. **Closed Loop Nature of Magnetic Field Lines**: Since the integral is zero, it reinforces the idea that magnetic field lines are closed loops. They do not start or end at any point but rather loop back on themselves. **Hint**: Visualize how magnetic field lines behave in space and how they connect back to themselves. 5. **Evaluating the Options**: - **Option A**: "Monopole can exist" - This is incorrect because the equation shows that monopoles cannot exist. - **Option B**: "Only dipole can exist" - This is also incorrect; while dipoles are present, the statement is misleading as it implies exclusivity. - **Option C**: "Magnetic field lines are closed loops" - This is correct, as established from the analysis. - **Option D**: "Net flux through the surface is 0" - This is misleading; while the integral is zero, it does not imply that the net flux through any arbitrary surface is zero. **Hint**: Carefully analyze each option in light of the implications of the equation. 6. **Conclusion**: The correct interpretation of the equation `oint vecB * d vecs = 0` leads us to conclude that magnetic field lines are indeed closed loops. Therefore, the correct answer is Option C. ### Final Answer: The correct answer is **C: Magnetic field lines are closed loops**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - B Objective Type Questions (One option is correct)|30 Videos
  • MAGNETISM AND MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section- C Linked Comprehension Type Questions|3 Videos
  • MAGNETISM AND MATTER

    AAKASH INSTITUTE ENGLISH|Exercise Try Yourself|53 Videos
  • LAWS OF MOTION

    AAKASH INSTITUTE ENGLISH|Exercise Assignment (SECTION-D) (Assertion-Reason Type Questions)|15 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    AAKASH INSTITUTE ENGLISH|Exercise SECTION - J|9 Videos

Similar Questions

Explore conceptually related problems

Maxwell’s equation laws of

Maxwell's equations describe the fundamental laws of

The Maxwell's equations are written as: (1)- [oint(bar E. bar ds) = (q_enclosed / epsilon_0)] , (2)- [oint(bar B. bar ds) = 0] ,(3)- [oint(bar E. bar dl) = d/dt {oint(bar B. bar ds)}] Which of the Maxwell's equations contains non-conservative electric field?

Let vec aa n d vec b be two non-zero perpendicular vectors. A vecrtor vec x satisfying the equation vec x xx vec b= vec a is vecx= beta vecb-1/|b|^2 vecaxx vecb then beta can be

If vec a_|_ vec b , then vector vec v in terms of vec aa n d vec b satisfying the equation s vec vdot vec a=0a n d vec vdot vec b=1a n d[ vec v vec a vec b]=1 is vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^2) b. vec b/(| vec b|^)+( vec axx vec b)/(| vec axx vec b|^2) c. vec b/(| vec b|^2)+( vec axx vec b)/(| vec axx vec b|^) d. none of these

If for an Amperian loop oint vec(B).vec(dl) = 0 does that mean vec(B) = 0 at every point on the Amperian loop ?

Let vec a=4hati+5hatj-hatk, vecb = hati -4hatj+5hatk and vec c=3hati+hatj-hatk . Find a vector vec d which is perpendicular to both vec c and vec b and vec d.vec a=21

Show that the equation vecrxxvecb=vec0(vecb!=vec0) has a solution iff veca.vecb!=0 .

A: In any magnetic field region the line integral ointvecB.vec(dl) along a closed loop is always zero. R: The magnetic field vecB in the expressioin oint vecB.vec(dl) is due to the currents enclosed only by the loop.

The condition for equations vec rxx vec a= vec ba n d vec rxx vec c= vec d to be consistent is vec bdot vec c= vec adot vec d b. vec adot vec b= vec c dot vec d c. vec bdot vec c+ vec adot vec d=0 d. vec adot vec b+ vec c dot vec d=0