Home
Class 12
MATHS
The formula giving the altitude y(m) in ...

The formula giving the altitude y(m) in terms of time t ( seconds ) of an object moving vertically is `y=y_(0)+v_(0)t-16t^(2)`, where `y_(0)` is initial altitude and `v_(0)` is initial velocity .
If `y_(0)=8 and v_(0)=48 m//s ` , what are the altitude , velocity and acceleration of the object when t=2s ?

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Write the altitude formula The altitude \( y(t) \) of the object is given by the formula: \[ y(t) = y_0 + v_0 t - 16t^2 \] where: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-A (Competition Level Questions)|50 Videos

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-B( Objective Type Questions ( One option is correct ))|31 Videos

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-J (Aakash Challengers Questions )|8 Videos

  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - I Aakash Challengers Questions|2 Videos

Similar Questions

Explore conceptually related problems

A particle moves with initial velocity v_(0) and retardation alphav , where v is velocity at any instant t. Then the particle

If velocity of a particle is given by v=(2t+3)m//s . Then average velocity in interval 0letle1 s is :

Knowledge Check

  • A particle moves in the x-y plane with velocity v_x = 8t-2 and v_y = 2. If it passes through the point x =14 and y = 4 at t =2s the equation of the path is

    A
    1. `x=y^3-y^2+2`
    B
    2. `x=y^2 - y+2`
    C
    3. `x=y^2 - 3y+2`
    D
    4. `x=y^3 - 2y^2 +2`

  • The position of and object moving along x-axis is given by x=a +bt^(2) , where a=8.5 m and b=2.5 ms^(-2) and (t) is measured in seconds. What is the velocity at t=0 s and t=2.0 s? What is the average velocity between t=2.0s and t=4.0 s ?

    A
    `5 m s^(-1)`
    B
    `10 m s^(-1)`
    C
    `15 m s^(-1)`
    D
    `20 m s^(-1)`

    • Similar Questions

    Explore conceptually related problems

    A particle at origin (0,0) moving with initial velocity u = 5 m/s hatj and acceleration 10 hati + 4 hatj . After t time it reaches at position (20,y) then find t & y

    If acceleration a(t) = 3t^(2) and initial velocity u=0 m/s , then the velocity of the particle after time t=4 s

    A particle moves with an initial velocity V_(0) and retardation alpha v , where alpha is a constant and v is the velocity at any time t. Velocity of particle at time is :

    The velocity of an object moving rectilinearly is given as a function of time by v=4t-3t^(2) where v is in m/s and t is in seconds. The average velocity if particle between t=0 to t=2 seconds is

    A particle moves in the x-y plane with velocity v_x = 8t-2 and v_y = 2. If it passes through the point x =14 and y = 4 at t = 2 s, the equation of the path is

    A particle moves in the x-y plane with velocity v_x = 8t-2 and v_y = 2. If it passes through the point x =14 and y = 4 at t = 2 s, the equation of the path is

    Home
    Profile