The formula giving the altitude y(m) in terms of time t ( seconds ) of an object moving vertically is `y=y_(0)+v_(0)t-16t^(2)`, where `y_(0)` is initial altitude and `v_(0)` is initial velocity .
If `y_(0)=8 and v_(0)=48 m//s ` , what are the altitude , velocity and acceleration of the object when t=2s ?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Write the altitude formula
The altitude \( y(t) \) of the object is given by the formula:
\[ y(t) = y_0 + v_0 t - 16t^2 \]
where:
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