Home
Class 12
MATHS
The slope of the tangent of the curve y=...

The slope of the tangent of the curve `y=int_0^x (dx)/(1+x^3)` at the point where `x = 1` is

A

`(1)/(2)`

B

`1`

C

`(1)/(4)`

D

`(1)/(5)`

Text Solution

Verified by Experts

The correct Answer is:
A
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-C( Objective Type Questions ( More than one option are correct ))|1 Videos
  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-C( Objective Type Questions ( More than one option is correct ))|5 Videos
  • APPLICATION OF DERIVATIVES

    AAKASH INSTITUTE ENGLISH|Exercise Assignment SECTION-A (Competition Level Questions)|50 Videos
  • APPLICATION OF INTEGRALS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment Section - I Aakash Challengers Questions|2 Videos

Similar Questions

Explore conceptually related problems

The slopes of the tangents to the curve y=(x+1)(x-3) at the points where it cuts the x - axis, are m_(1) and m_(2) , then the value of m_(1)+m_(2) is equal to

The slope of the tangent to the curve y=x^(2) -x at the point where the line y = 2 cuts the curve in the first quadrant, is

Knowledge Check

  • The slope of the tangent to the curve y=x^(3) -x +1 at the point whose x-coordinate is 2 is

    A
    `-11`
    B
    `(1)/(11)`
    C
    11
    D
    `3x^(2)-1`
  • Similar Questions

    Explore conceptually related problems

    Let f :[0,2pi] to [-3, 3] be a given function defined at f (x) = 3cos ""(x)/(2). The slope of the tangent to the curve y = f^(-1) (x) at the point where the curve crosses the y-axis is:

    The slope of the tangent to the curve (y-x^5)^2=x(1+x^2)^2 at the point (1,3) is.

    The slope of the tangent to the curve y=sqrt(4-x^2) at the point where the ordinate and the abscissa are equal is (a) -1 (b) 1 (c) 0 (d) none of these

    The slope of the tangent to the curve y=sqrt(4-x^2) at the point where the ordinate and the abscissa are equal is (a) -1 (b) 1 (c) 0 (d) none of these

    The slope of the tangent to the curve y =sqrt(9-x^(2)) at the point where ordinate and abscissa are equal, is

    The slope of the tangent to the curve y=sin^(-1) (sin x) " at " x=(3pi)/(4) is

    Find the equation of the tangent to the curve y=(x-7)/((x-2)(x-3) at the point where it cuts the x-axis.