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Let the circle x^2 + y^2 = 4 divide the ...

Let the circle `x^2 + y^2 = 4` divide the area bounded by tangent and normal at `(1, sqrt3)` and `x`-axis in `A_1 and A_2.` Then `A_1/A_2` equals to

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To solve the problem, we need to find the ratio \( \frac{A_1}{A_2} \), where \( A_1 \) and \( A_2 \) are the areas bounded by the tangent and normal at the point \( (1, \sqrt{3}) \) on the circle \( x^2 + y^2 = 4 \) and the x-axis. ### Step 1: Find the slope of the tangent at the point \( (1, \sqrt{3}) \). The equation of the circle is given by: \[ x^2 + y^2 = 4 \] ...
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Knowledge Check

  • If A_1 and A_2 are two AMs between a and b then (2A_1 -A_2) (2A_2 - A_1) =

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    B
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