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find the coordinate of a point where A(3...

find the coordinate of a point where `A(3, 4, 1 )` and `B(5, 1, 6)` connecting line intersect the plane XY

A

`(13/5, 23/5, 0)`

B

(0, 0, 0)

C

`(-13/5, -23/5, 0)`

D

`(-13/5, 23/5, 0)`

Text Solution

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The correct Answer is:
To find the coordinates of the point where the line connecting points A(3, 4, 1) and B(5, 1, 6) intersects the XY plane, we can follow these steps: ### Step 1: Determine the Direction Ratios The direction ratios of the line connecting points A and B can be calculated using the coordinates of these points. - Coordinates of A: \( A(3, 4, 1) \) - Coordinates of B: \( B(5, 1, 6) \) The direction ratios (d) can be calculated as follows: \[ d_x = x_B - x_A = 5 - 3 = 2 \] \[ d_y = y_B - y_A = 1 - 4 = -3 \] \[ d_z = z_B - z_A = 6 - 1 = 5 \] Thus, the direction ratios are \( (2, -3, 5) \). ### Step 2: Write the Parametric Equations of the Line Using point A and the direction ratios, we can write the parametric equations of the line: \[ \frac{x - 3}{2} = \frac{y - 4}{-3} = \frac{z - 1}{5} = t \] From this, we can express \( x, y, z \) in terms of \( t \): \[ x = 3 + 2t \] \[ y = 4 - 3t \] \[ z = 1 + 5t \] ### Step 3: Find the Intersection with the XY Plane The XY plane is defined by the equation \( z = 0 \). To find the intersection, we set \( z = 0 \) in the equation for \( z \): \[ 1 + 5t = 0 \] Solving for \( t \): \[ 5t = -1 \implies t = -\frac{1}{5} \] ### Step 4: Substitute \( t \) Back to Find \( x \) and \( y \) Now we substitute \( t = -\frac{1}{5} \) back into the equations for \( x \) and \( y \): For \( x \): \[ x = 3 + 2\left(-\frac{1}{5}\right) = 3 - \frac{2}{5} = \frac{15}{5} - \frac{2}{5} = \frac{13}{5} \] For \( y \): \[ y = 4 - 3\left(-\frac{1}{5}\right) = 4 + \frac{3}{5} = \frac{20}{5} + \frac{3}{5} = \frac{23}{5} \] ### Step 5: Write the Coordinates of the Intersection Point Thus, the coordinates of the point where the line intersects the XY plane are: \[ \left( \frac{13}{5}, \frac{23}{5}, 0 \right) \] ### Final Answer The coordinates of the intersection point are: \[ \left( \frac{13}{5}, \frac{23}{5}, 0 \right) \]
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AAKASH INSTITUTE ENGLISH-THREE DIMENSIONAL GEOMETRY -ASSIGNMENT SECTION - B
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