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Let A = {1, 2, 3}. Which of the followi...

Let A = {1, 2, 3}. Which of the following is not an equivalence relation on A ?

A

{(1,1), (2,2), (3,3)}

B

{(1,1), (2,2), (3,3), (1,2), (2,1)}

C

{(1,1), (2,2), (3,3), (2,3), (3,2)}

D

{(1,1), (2,2), (2,3)}

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given relations on the set A = {1, 2, 3} is not an equivalence relation, we need to check each relation against the three properties that define an equivalence relation: reflexivity, symmetry, and transitivity. ### Step-by-Step Solution: 1. **Understand the Properties of Equivalence Relations**: - **Reflexive**: For every element a in A, the pair (a, a) must be in the relation. - **Symmetric**: For any elements a and b in A, if (a, b) is in the relation, then (b, a) must also be in the relation. - **Transitive**: For any elements a, b, and c in A, if (a, b) and (b, c) are in the relation, then (a, c) must also be in the relation. 2. **Evaluate Each Relation**: - **Relation 1**: {(1, 1), (2, 2), (3, 3)} - Reflexive: Yes, all (a, a) are present. - Symmetric: Yes, since it only contains pairs of the form (a, a). - Transitive: Yes, since there are no pairs that violate transitivity. - **Conclusion**: This is an equivalence relation. - **Relation 2**: {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1)} - Reflexive: Yes, all (a, a) are present. - Symmetric: Yes, (1, 2) and (2, 1) are present. - Transitive: Yes, since (1, 2) and (2, 1) imply (1, 1) and (2, 2) which are present. - **Conclusion**: This is an equivalence relation. - **Relation 3**: {(1, 1), (2, 2), (3, 3), (2, 3), (3, 2)} - Reflexive: Yes, all (a, a) are present. - Symmetric: Yes, (2, 3) and (3, 2) are present. - Transitive: Yes, since (2, 3) and (3, 2) imply (2, 2) and (3, 3) which are present. - **Conclusion**: This is an equivalence relation. - **Relation 4**: {(1, 1), (2, 2), (2, 3)} - Reflexive: No, (3, 3) is missing. - Symmetric: Not applicable since it is not reflexive. - Transitive: Not applicable since it is not reflexive. - **Conclusion**: This is **not** an equivalence relation. 3. **Final Answer**: The relation that is not an equivalence relation is the fourth one.
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AAKASH INSTITUTE ENGLISH-RELATIONS AND FUNCTIONS -Assignment (Section - A) Objective Type Questions (one option is correct)
  1. Let a = {a, b, c} and R = {(a, a), (b, b), (c, c), (b, c), (a, b)} be ...

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  2. Let A = {1, 2, 3} and R = {(1, 1), (2,2), (1, 2), (2, 1), (1,3)} then ...

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  3. Let A = {1, 2, 3}. Which of the following is not an equivalence relat...

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  4. Which of the following relations is a function?

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  5. Let A = {1, 2, 3}, B = { 2, 3, 4} , then which of the following is a f...

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  6. The function f: NvecN(N is the set of natural numbers) defined by f(n)...

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  7. Let f : R rarr R be defined by f(x) = x^(2) - 3x + 4 for all x in R, t...

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  8. If f is a function form a set A to A, then f is invertible iff f is

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  9. Let f : R rarr R, g : R rarr R be two functions given by f(x) = 2x - 3...

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  10. Set A has 3 elements and set B has 4 elements. The number of injection...

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  11. Find the number of surjections from A to B, where A={1,2,3,4}, B={a,b}...

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  12. Let A and B be two finite sets having m and n elements respectively. T...

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  13. The total number of injective mappings from a set with m elements to a...

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  14. Let A be a set containing 10 distinct elements. Then the total number ...

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  15. Let E={1,2,3,4,} and F={1,2}. Then the number of onto functions from E...

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  16. If f : R rarr R, f(x) = 1/(x^2 - 1), then domain is

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  17. Function f :R->R,f(x) = x|x| is

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  18. domain of f(x) = (x^(2))/(1-x^(2)), is

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  19. Let f : N rarr N be defined as f(x) = 2x for all x in N, then f is

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  20. Let A={1,2,3,4,5,6}dot Define a relation R on set A by R={(x , y): y=x...

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