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A particle executes linear simple harmon...

A particle executes linear simple harmonic motion with an amplitude of `3 cm`. When the particle is at `2 cm` from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is

A

`(sqrt5)/(pi)`

B

`(sqrt5)/(2pi)`

C

`(4pi)/(sqrt5)`

D

`(2pi)/(sqrt3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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Knowledge Check

  • A particle executes linear simple harmonic motion with an amplitude of 2 cm . When the particle is at 1 cm from the mean position the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

    A
    `1/(2pisqrt(3))`
    B
    `2pisqrt3`
    C
    `(2pi)/(sqrt3)`
    D
    `sqrt3/(2pi)`

  • A particle executing simple harmonic motion with an amplitude A. The distance travelled by the particle in one time period is

    A
    zero
    B
    A
    C
    2A
    D
    4A

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