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A: Simple harmonic motion is not a unifo...

A: Simple harmonic motion is not a uniform motion.
R: Simple harmonic motion can be regarded as the projection of uniform circular motion.

A

If both Assertion & Reason are true and the reason is the correct explanation of the assertion, then mark (1)

B

If both Assertion & Reason are true but the reason is not the correct explanation of the assertion, then mark (2)

C

If Assertion is true statement but Reason is false then mark (3)

D

If both Assertion and Reason are false statements, then mark (4)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the assertion and reason about Simple Harmonic Motion (SHM), we can break it down into clear steps: ### Step 1: Analyze the Assertion The assertion states that "Simple harmonic motion is not a uniform motion." - **Explanation**: In SHM, the velocity of the oscillating object changes continuously. The formula for velocity in SHM is given by: \[ v = \omega \sqrt{A^2 - x^2} \] where \( \omega \) is the angular frequency, \( A \) is the amplitude, and \( x \) is the displacement from the mean position. Since \( x \) changes as the object oscillates, the velocity \( v \) also changes, indicating that SHM is a non-uniform motion. ### Step 2: Analyze the Reason The reason states that "Simple harmonic motion can be regarded as the projection of uniform circular motion." - **Explanation**: This statement is true. SHM can be visualized as the projection of a point moving in uniform circular motion onto a diameter of the circle. The equations for SHM can be expressed as: \[ x(t) = A \cos(\omega t) \quad \text{or} \quad x(t) = A \sin(\omega t) \] These equations represent the horizontal (or vertical) projection of a point moving around a circle with radius \( A \) at a constant angular speed \( \omega \). ### Step 3: Establish the Relationship Now, we need to determine if there is a relationship between the assertion and the reason. - **Explanation**: While both statements are true, the reason does not explain why SHM is a non-uniform motion. The reason describes a characteristic of SHM but does not provide a justification for the assertion that it is not uniform motion. ### Conclusion Based on the analysis: - The assertion is true: SHM is not a uniform motion. - The reason is also true: SHM can be viewed as the projection of uniform circular motion. - However, the reason does not explain the assertion. Thus, the correct answer is that both the assertion and reason are true, but the reason is not the correct explanation of the assertion. ### Final Answer **Option B**: Both assertion and reason are true, but the reason is not the correct explanation of the assertion. ---
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Knowledge Check

  • Simple harmonic motion is the projection of uniform circular motion on

    A
    x-axis
    B
    y-axis
    C
    reference circle
    D
    any diameter of reference circle
  • The equation of motion of a simple harmonic motion is

    A
    `(d^(2)x)/(dt^(2))=-omega^(2)x`
    B
    `(d^(2)x)/(dt^(2))=-omega^(2)t`
    C
    `(d^(2)x)/(dt^(2))=-omegax`
    D
    `(d^(2)x)/(dt^(2))=-omegat`
  • In simple harmonic motion, at the extreme positions

    A
    kinetic energy is minimum, potential energy is maximum
    B
    kinetic energy is maximum, potential energy is minimum
    C
    both kinetic and potential energies are maximum.
    D
    both kinetic and potential energies are minimum
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