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For the reaction, 2A + B rarr 3C + D, wh...

For the reaction, `2A + B rarr 3C + D`, which of the following does not express the reaction rate

A

`-(d[C])/(3dt)`

B

`-(d[B])/(dt)`

C

`(d[D])/(dt)`

D

`-(d[A])/(2dt)`

Text Solution

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The correct Answer is:
To determine which expression does not represent the reaction rate for the reaction \(2A + B \rightarrow 3C + D\), we need to understand how the reaction rate is defined in terms of the stoichiometric coefficients of the reactants and products. ### Step-by-Step Solution: 1. **Identify the Reaction:** The given reaction is: \[ 2A + B \rightarrow 3C + D \] 2. **Define Reaction Rate:** The rate of a reaction can be expressed in terms of the change in concentration of reactants and products over time. For a general reaction: \[ aA + bB \rightarrow cC + dD \] The rate can be expressed as: \[ \text{Rate} = -\frac{1}{a}\frac{d[A]}{dt} = -\frac{1}{b}\frac{d[B]}{dt} = \frac{1}{c}\frac{d[C]}{dt} = \frac{1}{d}\frac{d[D]}{dt} \] 3. **Apply to Given Reaction:** For our reaction: - The stoichiometric coefficients are: - \(A: 2\) - \(B: 1\) - \(C: 3\) - \(D: 1\) Therefore, the reaction rate can be expressed as: \[ \text{Rate} = -\frac{1}{2}\frac{d[A]}{dt} = -\frac{1}{1}\frac{d[B]}{dt} = \frac{1}{3}\frac{d[C]}{dt} = \frac{1}{1}\frac{d[D]}{dt} \] 4. **Evaluate Each Option:** Now, let's evaluate the options provided to see which one does not express the reaction rate correctly: - **Option 1:** \(-\frac{1}{3}\frac{d[C]}{dt}\) - This is incorrect because the rate of appearance of \(C\) should be \(\frac{1}{3}\frac{d[C]}{dt}\) (not negative). - **Option 2:** \(-\frac{d[B]}{dt}\) - This is correct as it represents the rate of disappearance of \(B\). - **Option 3:** \(\frac{d[D]}{dt}\) - This is correct as it represents the rate of appearance of \(D\). - **Option 4:** \(-\frac{1}{2}\frac{d[A]}{dt}\) - This is correct as it represents the rate of disappearance of \(A\). 5. **Conclusion:** The expression that does not represent the reaction rate is: \[ \text{Option 1: } -\frac{1}{3}\frac{d[C]}{dt} \]
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