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If the masses of Cr and O are in the rat...

If the masses of Cr and O are in the ratio 13 : 12 in CrO3, then the ratio of O that cobines with the same mass of Cr in Cr2O3 and Cr2O7 is

A

`1 : 2`

B

`1 : 4`

C

`3 : 7`

D

`2 : 5`

Text Solution

AI Generated Solution

The correct Answer is:
To find the ratio of oxygen that combines with the same mass of chromium in Cr2O3 and Cr2O7, we can follow these steps: ### Step 1: Determine the molar masses of Cr and O - The molar mass of chromium (Cr) is approximately 52 g/mol. - The molar mass of oxygen (O) is approximately 16 g/mol. ### Step 2: Calculate the mass ratio in CrO3 - In CrO3, the ratio of Cr to O is given as 13:12. - This means that for every 13 grams of Cr, there are 12 grams of O. - Since CrO3 contains 1 Cr and 3 O, we can find the mass of oxygen that combines with 1 gram of Cr. ### Step 3: Find the mass of O that combines with 1 g of Cr in CrO3 - From the ratio, if 13 g of Cr combines with 12 g of O, then: \[ \text{Mass of O per gram of Cr} = \frac{12 \text{ g O}}{13 \text{ g Cr}} = \frac{12}{13} \text{ g O} \] ### Step 4: Calculate the mass of O in Cr2O3 - In Cr2O3, there are 2 Cr and 3 O. - The total mass of Cr in Cr2O3 is: \[ 2 \times 52 \text{ g} = 104 \text{ g} \] - The total mass of O in Cr2O3 is: \[ 3 \times 16 \text{ g} = 48 \text{ g} \] - The mass of O that combines with 104 g of Cr is 48 g. ### Step 5: Find the mass of O that combines with 1 g of Cr in Cr2O3 - The mass of O per gram of Cr in Cr2O3 is: \[ \text{Mass of O per gram of Cr} = \frac{48 \text{ g O}}{104 \text{ g Cr}} = \frac{48}{104} = \frac{12}{26} = \frac{6}{13} \text{ g O} \] ### Step 6: Calculate the mass of O in Cr2O7 - In Cr2O7, there are 2 Cr and 7 O. - The total mass of O in Cr2O7 is: \[ 7 \times 16 \text{ g} = 112 \text{ g} \] - The mass of O that combines with 104 g of Cr in Cr2O7 is 112 g. ### Step 7: Find the mass of O that combines with 1 g of Cr in Cr2O7 - The mass of O per gram of Cr in Cr2O7 is: \[ \text{Mass of O per gram of Cr} = \frac{112 \text{ g O}}{104 \text{ g Cr}} = \frac{112}{104} = \frac{28}{26} = \frac{14}{13} \text{ g O} \] ### Step 8: Calculate the ratio of O in Cr2O3 to Cr2O7 - Now we have: - Mass of O per gram of Cr in Cr2O3 = \( \frac{6}{13} \) - Mass of O per gram of Cr in Cr2O7 = \( \frac{14}{13} \) - The ratio of O in Cr2O3 to O in Cr2O7 is: \[ \text{Ratio} = \frac{\frac{6}{13}}{\frac{14}{13}} = \frac{6}{14} = \frac{3}{7} \] ### Final Answer The ratio of oxygen that combines with the same mass of chromium in Cr2O3 to Cr2O7 is **3:7**. ---
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