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A bob of mass 2kg is suspended from poin...

A bob of mass `2kg` is suspended from point `O` of a core with an inextensible string strinng of length `sqrt(3)m`. It is moving in horizontal circle over the surface of cone as shown in the figure. Then `:(g=10m//s^(2))`

A

bob looses contact with cone it `v gt sqrt(5) m//s`

B

normal force on bob is `19 N` when `v = 2 m//s`

C

tension in string is `(38)/(sqrt(3))`N when `v = 2m//s`

D

normal force on bob is `(17)/(sqrt(3))` N when `v = 2m//s`

Text Solution

Verified by Experts

The correct Answer is:
A, C


`T cos 30^(@) +N sin 30^(@) =mg`
`rArr sqrt(3) T+ N = 2mg`...(i)
`T sin 30^(@) -N cos 30^(@) = (mv^(2))/((sqrt(3)//2))`
`rArr T sin 30^(@) - 3 N = 4mv_(2)`
`sqrt(3)T - 3N =4mv_(2)`....(ii)
by (i),(ii) `rArr N =(2mg-4mv^(2))/(4)`
`T = (6mg-4mv^(2))/(4 sqrt(3))`
for `N gt0 rArr v lt sqrt(5) m//s`
at `v = 2 T = (38)/(sqrt(3)) N , N = 2 N`.
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Knowledge Check

  • A block fof mass 5kg is suspended by a massless rope of length 2 m from the ceilling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g=10ms^(-2)m .

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