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Starting with a sample of pure ""^(66)Cu...

Starting with a sample of pure `""^(66)Cu,(7)/(8)` of it decays into Zn in 15 min. The corresponding half-life is

A

`10` minute

B

`15` minute

C

`5` minute

D

`7(1)/(2)`minute

Text Solution

Verified by Experts

The correct Answer is:
C
`N=N_(0)(1-e^(-lambdat))`
`rArr (N_(0)-N)/(N_(0))=e^(-lambdat)`
`:. (1)/(8)=e^(-lambdat)`
`rArr 8=e^(lambdat t)" "rArr 3 ln 2=lambda t " "rArr=(3xx0.693)/(15)`
`t_(1//2)=(0.693)/(3xx0.693)xx15" "t_(1//2)=5 min`
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Knowledge Check

  • Radioactive carbon dating can determine how long ago an organism lived by measuring how much of thte ""^(14) C in the sample has decayed. ""^(14)C is an isotope of carbon that has a half-life of 5,600 years.Half-life is the amount of time it takes for half of the original amount to decay. If a sample of a petrified tree contains 6.25 percent of its original ""^(14)C, how long ago did the tree die ?

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    D
    89,600 years

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