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When a deuteron of mass 2.0141 a.m.u and...

When a deuteron of mass 2.0141 a.m.u and negligible K.E. is absorbed by a Lithium `(._(3)Li^(6))` nucleus of mass 6.0155 a.m.u. the compound nucleus disintegration spontaneously into two alpha particles, each of mass 4.0026 a.m.u. Calculate the energy carried by each `alpha` particle.

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To solve the problem, we will follow these steps: ### Step 1: Calculate the Initial Mass The initial mass is the sum of the masses of the deuteron and the lithium nucleus. \[ \text{Initial Mass} = \text{Mass of Deuteron} + \text{Mass of Lithium} \] ...
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