The kinetic energy of an electron accelerated from rest through a potential difference of 5V will be:

Options

A. 5 J
B. 5 eV
C. 5 erg
D. None of these

Explanation

To find the kinetic energy of an electron accelerated from rest through a potential difference of 5V, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between potential difference and kinetic energy**:
When an electron is accelerated through a potential difference (V), it gains kinetic energy (KE). The kinetic energy gained by the electron is equal to the work done on it by the electric field, which can be expressed as:
\[ KE = eV \]
where \( e \) is the charge of the electron (approximately \( 1.6 \times 10^{-19} \) coulombs) and \( V \) is the potential difference in volts.

2. **Substitute the given values**:
Here, the potential difference \( V \) is given as 5 volts. Therefore, we can substitute this value into the equation:
\[ KE = e \times 5 \]

3. **Convert the kinetic energy to electron volts**:
Since the charge of the electron \( e \) is defined as 1 electron volt (1 eV) when it is accelerated through a potential difference of 1 volt, we can directly say:
\[ KE = 5 \text{ eV} \]

4. **Final result**:
Thus, the kinetic energy of the electron accelerated from rest through a potential difference of 5V is:
\[ KE = 5 \text{ eV} \]

### Final Answer:
The kinetic energy of an electron accelerated from rest through a potential difference of 5V will be **5 electron volts (5 eV)**.