Home
Class 12
CHEMISTRY
All of the water in a 0.20M solution of ...

All of the water in a `0.20M` solution of `NaCl` was evaporated and a `0.150` mol of `NaCl` was obtained. What the original volume of the sample?

A

`30mL`

B

`333mL`

C

`750mL`

D

`1000mL`

Text Solution

AI Generated Solution

The correct Answer is:
To find the original volume of the `0.20 M` NaCl solution from which `0.150 moles` of NaCl was obtained after evaporation, we can use the formula for molarity: ### Step-by-Step Solution: 1. **Understand the Molarity Formula**: Molarity (M) is defined as the number of moles of solute divided by the volume of solution in liters. \[ M = \frac{\text{Number of moles of solute}}{\text{Volume of solution in liters}} \] 2. **Identify the Given Values**: - Molarity (M) = `0.20 M` - Number of moles of NaCl = `0.150 moles` 3. **Rearrange the Molarity Formula**: To find the volume of the solution, we can rearrange the formula: \[ \text{Volume of solution in liters} = \frac{\text{Number of moles of solute}}{M} \] 4. **Substitute the Known Values**: Now, substitute the values into the rearranged formula: \[ \text{Volume} = \frac{0.150 \text{ moles}}{0.20 \text{ M}} \] 5. **Calculate the Volume**: \[ \text{Volume} = \frac{0.150}{0.20} = 0.75 \text{ liters} \] 6. **Convert the Volume to Milliliters**: Since the question may require the answer in milliliters, convert liters to milliliters: \[ 0.75 \text{ liters} \times 1000 \text{ ml/liter} = 750 \text{ ml} \] ### Final Answer: The original volume of the sample is **750 ml**.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-2(PART-4)|4 Videos
  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-3(PART-1)|14 Videos
  • SOLUTIONS

    RESONANCE ENGLISH|Exercise EXERCISE-2(PART-1)|25 Videos
  • SOLUTION AND COLLIGATIVE PROPERTIES

    RESONANCE ENGLISH|Exercise PHYSICAL CHEMITRY (SOLUTION & COLLIGATIVE PROPERTIES)|52 Videos
  • STEREOISOMERISM

    RESONANCE ENGLISH|Exercise EXERCISE (PART III : PRACTICE TEST-2 (IIT-JEE (ADVANCED PATTERN))|23 Videos

Similar Questions

Explore conceptually related problems

The pH value of 0.001M aqueous solution of NaCl is

4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molality of the resultant solution is……..

Knowledge Check

  • 4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molality of the resultant solution is……..

    A
    0.004
    B
    0.008
    C
    0.012
    D
    0.016
  • Similar Questions

    Explore conceptually related problems

    What is the molarity of 0.1 moles of NaCl dissolved in a solution which has a total volume of 500 mL?

    100 ml of a colloidal solution is completely precipitated by addition of 0.5 ml 1M NaCl solution, calculate the coagulation value of NaCl.

    100 ml of 0.1 M NaCl and 100 ml of 0.2 MNaOH are mixed. What is the change in pH of NaCI solution ?

    For the coagulation of 200 mL of As_(2)S_(3) solution, 10 mL of 1 M NaCl is required. What is the coagulating value of NaCl.

    For the coagulation of 200 mL of As_(2)S_(3) solution, 10 mL of 1 M NaCl is required. What is the coagulating value of NaCl.

    200 mL of 0.4M solution of CH_(3)COONa is mixed with 400 mL of 0.2 M solution of CH_(3)COOH . After complete mixing, 400 mL of 0.1 M NaCl is added to it. What is the pH of the resulting solution? [K_(a) of CH_(3)COOH=10^(-5)]

    A 20.0mL sample of CuSO_(4) solution was evaporated to dryness, leaving 0.967g of residue. What was the molarity of the original solution ? (Cu=63.5)