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A toroid has 2000 turns. The inner & out...

A toroid has `2000` turns. The inner & outer radii of its core are `11cm` and `12cm` respectively. The magnetic field in the core for a current of `0*7A` is `2*5T`. What is relative permeability of core?

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To find the relative permeability of the core of the toroid, we can follow these steps: ### Step 1: Calculate the Mean Radius The mean radius \( r \) of the toroid can be calculated using the inner radius \( r_1 \) and the outer radius \( r_2 \): \[ r = \frac{r_1 + r_2}{2} \] Given: - Inner radius \( r_1 = 11 \, \text{cm} = 0.11 \, \text{m} \) - Outer radius \( r_2 = 12 \, \text{cm} = 0.12 \, \text{m} \) Calculating: \[ r = \frac{0.11 + 0.12}{2} = \frac{0.23}{2} = 0.115 \, \text{m} \] ### Step 2: Use the Formula for Magnetic Field in a Toroid The magnetic field \( B \) in a toroid is given by the formula: \[ B = \mu_0 \cdot \mu_r \cdot \frac{N \cdot I}{2 \pi r} \] Where: - \( \mu_0 = 4\pi \times 10^{-7} \, \text{T m/A} \) (permeability of free space) - \( \mu_r \) is the relative permeability (what we need to find) - \( N \) is the number of turns (2000) - \( I \) is the current (0.7 A) - \( r \) is the mean radius (0.115 m) ### Step 3: Rearranging the Formula Rearranging the formula to solve for \( \mu_r \): \[ \mu_r = \frac{B \cdot 2 \pi r}{\mu_0 \cdot N \cdot I} \] ### Step 4: Substitute the Values Substituting the known values into the rearranged formula: \[ B = 2.5 \, \text{T}, \quad r = 0.115 \, \text{m}, \quad N = 2000, \quad I = 0.7 \, \text{A} \] \[ \mu_r = \frac{2.5 \cdot 2 \pi \cdot 0.115}{(4\pi \times 10^{-7}) \cdot 2000 \cdot 0.7} \] ### Step 5: Simplifying the Expression Calculating the numerator: \[ \text{Numerator} = 2.5 \cdot 2 \cdot \pi \cdot 0.115 = 0.5775 \pi \] Calculating the denominator: \[ \text{Denominator} = (4\pi \times 10^{-7}) \cdot 2000 \cdot 0.7 = 5.6 \times 10^{-4} \pi \] ### Step 6: Final Calculation Now substituting back: \[ \mu_r = \frac{0.5775 \pi}{5.6 \times 10^{-4} \pi} = \frac{0.5775}{5.6 \times 10^{-4}} \approx 1031.25 \] Thus, the relative permeability \( \mu_r \) is approximately \( 1031.25 \). ### Final Answer \[ \mu_r \approx 1031.25 \] ---
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Knowledge Check

  • A ring of mean radius 15 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. The magnetic field in the core for a magnetising current of 1.2 A is

    A
    2.48T
    B
    3.48T
    C
    4.48T
    D
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  • The inner and outer radius of a toroid core are 28 cm and 29 cm respectively and around the core 3700 turns of a wire are wounded. If the current in the wire is 10 A, then the magnetic field inside the core of the toroid is

    A
    `2.60 xx 10^(-2)T`
    B
    `2.60 xx 10^(-3)T`
    C
    `4.52 xx 10^(-2)T`
    D
    `4.52 xx 10^(-3)T`
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