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An alpha particle is moving along a circ...

An `alpha` particle is moving along a circle of radius R with a constant angular velocity `omega`. Point A lies in the same plane at a distance 2R from the centre. Point A records magnetic field produced by the `alpha` particle. If the minimum time interval between two successive times at which A records zero magnetic field is `t_(1)`, the angular speed `omega` in terms of t is

A

`(2pi)/t`

B

`(2pi)/3t`

C

`pi/3t`

D

`pi/t`

Text Solution

Verified by Experts

The correct Answer is:
B
Point `A` shall record zero magnetic field (due to `alpha`-particle) when the `alpha`-particle is at position `P` and `Q` as shown in figure.The time taken by `alpha`-particle to go from `P` to `Q` is
`t=1/3(2pi)/omega` or `omega=(2pi)/(3t)`
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