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A charge of 1 coulumb is placed is one e...

A charge of `1` coulumb is placed is one end of a non-conducting rod of length `0.6m`.The rod is rotated in a vertical plane about a horizontal axis passing through the other end of the rod with an angular velocity `10^(4)pi rad//sec`.Find the magnetic field at a point on the axis of rotation of a distance of `0.8m` from the centre of the path is `Npixx10^(-4) T`,then find value of `N`.

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To solve the problem step by step, we will follow the given information and apply the relevant formulas for calculating the magnetic field due to a rotating charge. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Charge, \( q = 1 \, \text{C} \) - Length of the rod, \( L = 0.6 \, \text{m} \) - Angular velocity, \( \omega = 10^4 \pi \, \text{rad/s} \) ...
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