How many alcohols give immediate turbidity with Lucas reagent having molecular formula `(C_(5)H_(12)O)` :

Options

A. `1`
B. `2`
C. `3`
D. `4`

Explanation

To determine how many alcohols with the molecular formula \(C_5H_{12}O\) give immediate turbidity with Lucas reagent, we can follow these steps:

### Step 1: Understand the Lucas Reagent
Lucas reagent is a mixture of anhydrous zinc chloride and concentrated hydrochloric acid. It is used to differentiate between primary, secondary, and tertiary alcohols based on the rate at which they react to form alkyl chlorides.

### Step 2: Identify the Types of Alcohols
- **Primary alcohols**: React slowly with Lucas reagent, showing turbidity after some time.
- **Secondary alcohols**: React within a few minutes, showing turbidity.
- **Tertiary alcohols**: React immediately, showing turbidity right away.

### Step 3: Analyze the Molecular Formula
The molecular formula given is \(C_5H_{12}O\). We need to identify how many of these alcohols can be tertiary alcohols.

### Step 4: Determine Possible Structures
To find the structures of alcohols with the formula \(C_5H_{12}O\):
1. **Tertiary Alcohols**: A tertiary alcohol has the hydroxyl group (\(-OH\)) attached to a carbon that is bonded to three other carbons.
2. For \(C_5H_{12}O\), we can draw the following structures:
- **2-Pentanol**: This is a secondary alcohol, so it won't give immediate turbidity.
- **3-Pentanol**: This is also a secondary alcohol.
- **2-Methyl-2-butanol**: This is a tertiary alcohol.

### Step 5: Count the Tertiary Alcohols
From the structures we analyzed:
- **2-Methyl-2-butanol** is the only tertiary alcohol that can be formed from \(C_5H_{12}O\).

### Conclusion
Thus, there is only **one tertiary alcohol** that gives immediate turbidity with Lucas reagent.

### Final Answer
The answer is **1**.

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