Home
Class 12
CHEMISTRY
What is Delta U when 2.0 mole of liquid ...

What is `Delta U` when `2.0` mole of liquid water vaporises at `100^(@)C`? The heat of vaporisation `(Delta H_("vap".))` of water at `100^(@)C` is `40.66 KJmol^(-1)`.

Text Solution

AI Generated Solution

To find the change in internal energy (ΔU) when 2.0 moles of liquid water vaporizes at 100°C, we can use the relationship between the heat of vaporization (ΔH) and the change in internal energy (ΔU). The relevant equation is: \[ \Delta H = \Delta U + \Delta n_g RT \] Where: - ΔH is the heat of vaporization ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise -1 Part -II Only option correct type|92 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise Exercise -2 Part-I: Only one option correct type|23 Videos
  • THERMODYNAMICS

    RESONANCE ENGLISH|Exercise G-2|1 Videos
  • TEST SERIES

    RESONANCE ENGLISH|Exercise CHEMISTRY|50 Videos

Similar Questions

Explore conceptually related problems

At 100^(@)C, the P^(H) of pure water is

Calculate the entropy change when one mole of water at 373 K is converted into steam. Latent heat of vaporisation of water (DeltaH_(v)) is 40.7 xx 10^(3) J mol^(-1)

One moles of strem is compressed reversibly of water at boiling point 100^(@)C . The heat of vapourisation of water at 100^(@)C and 1atm is 540cal g^(-1) . Calculate DeltaU and DeltaH .

Calculate the entropy change when 3.6g of liquid water is completely converted into vapour at 100^(@)C . The molar heat of vaporization is 40.85KJ mol^(-1) .

18g of water is taken to prepare the tea. Find out the internal energy of vaporisation at 100^(@) C. (Delta_(vap)H for water at 373 K is 40.66kJ mol^(-1))

90 g of water spilled out from a vessel in the room on the floor. Assuming that water vapour behaving as an ideal gas, calculate the internal energy change when the spilled water undergoes complete evaporation at 100^(@)C . (Given the molar enthalpy of vaporisation of water at 1 bar and 373 K = 41 kJ mol^(-1) ).

90 g of water spilled out from a vessel in the room on the floor. Assuming that water vapour behaving as an ideal gas, calculate the internal energy change when the spilled water undergoes complete evaporation at 100^(@)C . (Given the molar enthalpy of vaporisation of water at 1 bar and 373 K = 41 kJ mol^(-1) ).

The enthalpy of vaporisation of water at 100^(@)C is 40.63 KJ mol^(-1) . The value Delta E for the process would be :-

Entropy of vaporisation of water at 100^(@)C , if molar heat of vaporisation is 8710 cal mol^(-1) will be

The internal energy change (in J) when 90 g of water undergoes complete evaporation at 100^(@)C is ______ . (Given : Delta H_("vap") for water at 373 K = 41 kJ/ mol , R = 8.314 JK^(-1) mol^(-1) )