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Select the most basic compound....

Select the most basic compound.

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To determine the most basic compound among the given structures, we need to analyze the substituents attached to the aniline (C6H5NH2) and their effects on the basicity of the nitrogen atom. ### Step-by-Step Solution: 1. **Identify the Structures**: We have four structures of aniline with different substituents at the meta position. Let's denote them as: - Structure 1: Aniline with a -NO2 (nitro) group - Structure 2: Aniline with a -Cl (chloro) group - Structure 3: Aniline with a -CH3 (methyl) group - Structure 4: Aniline with a -F (fluoro) group 2. **Understand Basicity**: Basicity in organic compounds is often related to the ability of the nitrogen atom to donate its lone pair of electrons. The presence of electron-withdrawing groups (EWGs) decreases basicity, while electron-donating groups (EDGs) increase basicity. 3. **Analyze Each Structure**: - **Structure 1 (-NO2)**: The nitro group is a strong electron-withdrawing group (-I effect). It pulls electron density away from the nitrogen, making it less able to donate its lone pair. Thus, this structure is non-basic. - **Structure 2 (-Cl)**: Chlorine is also an electron-withdrawing group, but it has a weaker -I effect compared to -NO2. It still decreases the basicity of the nitrogen, but not as significantly as the nitro group. Therefore, it is less basic than aniline but more basic than Structure 1. - **Structure 3 (-CH3)**: The methyl group is an electron-donating group (+I effect). It increases the electron density on the nitrogen, making it more basic. Thus, this structure is more basic than Structures 1 and 2. - **Structure 4 (-F)**: Fluorine is a strong electron-withdrawing group due to its high electronegativity (-I effect), which decreases the basicity of the nitrogen. However, it also has a +M effect (mesomeric effect) that can stabilize the lone pair to some extent. Still, it is less basic than Structure 3. 4. **Conclusion**: Comparing the basicity of all four structures, Structure 3 with the -CH3 (methyl) group is the most basic due to its +I effect, which enhances the ability of the nitrogen to donate its lone pair of electrons. ### Final Answer: The most basic compound is **Structure 3 (Aniline with a -CH3 group)**. ---
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RESONANCE ENGLISH-GENERAL ORGANIC CHEMISTRY II-(APSP) Part-I:Practice Test-1
  1. Which is less basic than benzyl carbanion ?

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  2. The decreasing order of acidic strength among trichloroacetic acid (I)...

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  3. Consider the following carbanions (i) CH(3)- overset(Ө)CH(2)" "(ii...

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  4. The order of stability of the following carbocations:

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  5. The most stable carbocation is

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  6. Pyridine is less basic than triethylamine because

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  7. Which is the following phenol has lowest pK(a) ?

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  8. Which is most basic among the followings ?

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  9. Assertion:The pK(a) of acetic acid is lower than that of phenol. Reaso...

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  10. The order of stability of the following tautomeric compounds is : un...

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  11. Observe the following feasible reaction: Q. Identify the feasible...

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  12. In which of following carbocation rearragement take place with change ...

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  13. Observer the following reaction sequence. Which is correct acidic...

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  14. Most stable carbocation among the following is

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  15. Select the most basic compound.

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  16. Which of the following compounds will have highest enolic content?

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  17. The hydride ion H^(-) is stronger base than its hydroxide ion OH^(-) W...

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  18. Give the stability order of following radicals :

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  19. The most stable carbanion among the following is

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  20. Which of the following is the most stabilized carbocation ?

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