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Find the range of the following functio...

Find the range of the following functions: (where {.} and [.] represent fractional part and greatest integer part functions respectively)
`f(x)=1-|x-2|`

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To find the range of the function \( f(x) = 1 - |x - 2| \), we will analyze the function step by step. ### Step 1: Understand the Absolute Value Function The absolute value function \( |x - 2| \) can be defined piecewise: - For \( x \geq 2 \), \( |x - 2| = x - 2 \) - For \( x < 2 \), \( |x - 2| = -(x - 2) = 2 - x \) ### Step 2: Define the Function Piecewise Using the definition of the absolute value, we can express \( f(x) \) as: - For \( x \geq 2 \): \[ f(x) = 1 - (x - 2) = 3 - x \] - For \( x < 2 \): \[ f(x) = 1 - (2 - x) = x - 1 \] ### Step 3: Analyze Each Piece Now we will analyze the two pieces of the function separately to determine their ranges. 1. **For \( x \geq 2 \)**: \[ f(x) = 3 - x \] As \( x \) increases from \( 2 \) to \( \infty \), \( f(x) \) decreases from \( 1 \) to \( -\infty \). Therefore, the range for this piece is: \[ (-\infty, 1] \] 2. **For \( x < 2 \)**: \[ f(x) = x - 1 \] As \( x \) decreases from \( 2 \) to \( -\infty \), \( f(x) \) increases from \( 1 \) to \( -\infty \). Therefore, the range for this piece is: \[ (-\infty, 1) \] ### Step 4: Combine the Ranges The overall range of the function \( f(x) \) combines the ranges from both pieces: - From the first piece, we have \( (-\infty, 1] \) - From the second piece, we have \( (-\infty, 1) \) Since both ranges extend to \( -\infty \) and the maximum value is \( 1 \), the combined range of \( f(x) \) is: \[ (-\infty, 1] \] ### Final Answer The range of the function \( f(x) = 1 - |x - 2| \) is: \[ (-\infty, 1] \]

To find the range of the function \( f(x) = 1 - |x - 2| \), we will analyze the function step by step. ### Step 1: Understand the Absolute Value Function The absolute value function \( |x - 2| \) can be defined piecewise: - For \( x \geq 2 \), \( |x - 2| = x - 2 \) - For \( x < 2 \), \( |x - 2| = -(x - 2) = 2 - x \) ### Step 2: Define the Function Piecewise ...
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