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If (2x+y,7)=(5,y-3) then find x and y...

If `(2x+y,7)=(5,y-3)` then find `x` and `y`

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To solve the equation \((2x+y, 7) = (5, y-3)\), we will equate the corresponding components of the ordered pairs. ### Step 1: Set up the equations From the given equation, we can separate it into two equations: 1. \(2x + y = 5\) (from the first components) 2. \(7 = y - 3\) (from the second components) ### Step 2: Solve the second equation for \(y\) From the second equation \(7 = y - 3\), we can solve for \(y\): \[ y - 3 = 7 \] Adding 3 to both sides gives: \[ y = 10 \] ### Step 3: Substitute \(y\) into the first equation Now that we have \(y = 10\), we can substitute this value into the first equation \(2x + y = 5\): \[ 2x + 10 = 5 \] ### Step 4: Solve for \(x\) Now, we will solve for \(x\): \[ 2x + 10 = 5 \] Subtracting 10 from both sides gives: \[ 2x = 5 - 10 \] \[ 2x = -5 \] Dividing both sides by 2 gives: \[ x = -\frac{5}{2} \] ### Final Answer Thus, the values of \(x\) and \(y\) are: \[ x = -\frac{5}{2}, \quad y = 10 \]

To solve the equation \((2x+y, 7) = (5, y-3)\), we will equate the corresponding components of the ordered pairs. ### Step 1: Set up the equations From the given equation, we can separate it into two equations: 1. \(2x + y = 5\) (from the first components) 2. \(7 = y - 3\) (from the second components) ### Step 2: Solve the second equation for \(y\) ...
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