Find the valency factor for following bases :
`(i) Ca(OH)_(2) " " (ii) CsOH " " (iii) Al(OH)_(3)`

Answer

To find the valency factor for the given bases, we need to determine the number of hydroxide ions (OH⁻) released per formula unit of each base when they dissociate in solution.

### Step-by-step Solution:

1. **Identify the first base: Ca(OH)₂**
- When calcium hydroxide, Ca(OH)₂, dissociates in water, it breaks down into:
\[ \text{Ca(OH)}_2 \rightarrow \text{Ca}^{2+} + 2 \text{OH}^- \]
- Here, 2 hydroxide ions (OH⁻) are released per molecule of Ca(OH)₂.
- **Valency factor for Ca(OH)₂ = 2**

2. **Identify the second base: CsOH**
- When cesium hydroxide, CsOH, dissociates in water, it breaks down into:
\[ \text{CsOH} \rightarrow \text{Cs}^+ + \text{OH}^- \]
- Here, 1 hydroxide ion (OH⁻) is released per molecule of CsOH.
- **Valency factor for CsOH = 1**

3. **Identify the third base: Al(OH)₃**
- When aluminum hydroxide, Al(OH)₃, dissociates in water, it breaks down into:
\[ \text{Al(OH)}_3 \rightarrow \text{Al}^{3+} + 3 \text{OH}^- \]
- Here, 3 hydroxide ions (OH⁻) are released per molecule of Al(OH)₃.
- **Valency factor for Al(OH)₃ = 3**

### Summary of Valency Factors:
- For Ca(OH)₂: **Valency factor = 2**
- For CsOH: **Valency factor = 1**
- For Al(OH)₃: **Valency factor = 3**